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Please someone help me with this question :
June 2008 P3 No. 6
June 2008 P3 No. 6
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need help with question 7 ii) october/november 2008 mechanics M1
how come the constant is 5 when we integrated the acceleration ?
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w08_qp_2.pdf
Please someone help me with this question :
June 2008 P3 No. 6
thanks for the reply.
Here it is . Please help me. Thanks in advance.
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s08_qp_3.pdf
It's number 6
No problem. Peace.thanks for the reply.
Someone please help me with this question :
Nov 2009 P3 Question 1
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w09_qp_31.pdf
I just dont understand why 5/4 has been rejected and how do we get x > -1/2
Try squaring both sides and shift all terms to one side of the inequality before trying to work things out.
Hope this might help a little. Peace.
Any other doubts?that i can help in that paper!!I tried it. i got a quadratic inequality. Then from here i dont know what to do .
Please elaborate .
Thank you
http://www.xtremepapers.com/papers/...AS Level/Mathematics (9709)/9709_w08_qp_4.pdfThe attachment you provided is the pure math portion, not mechanics. Please do check again. Peace.
You would have to differentiate both sides wrt x,
ie dy/dx = 4x + (-4x^3)* (e^-x^4) and set dy/dx=0.
To obtain the roots of this equation, you will have to use your graphic calculator.
Subsequently, you can either use the second order derivative or the sign test method to ascertain the nature of the stationary values.
Hope this helps. Peace.
but how to find the roots? this is where i was stuck... :-(
can't simplify it further after differentiating it...
my calculator doesn't have that option, n i think to show the working is imp instead of directly writing the roots from the calculator...
Show that the points (7,12), (-3,-12) and (14,-5) lie on a circle with centre (2,0).
Plz help
Thnx in advanc
(x-2)^2 + y^2 =r^2 is this a formula used to find the solution for these type of questions?The equation of this particular circle is simply (x-2)^2 + y^2 =r^2, where r denotes the radius of the circle.
Substitute one set of coordinates into the above equation to compute the value of r, and subsequently substitute
the remaining two sets of coordinates to verify they satisfy the circle equation.
Hope this helps. Peace.
Just find the distance between the points. Having the same distance from (2,0) shows its a circle. Just use the hypotunus theorem.Show that the points (7,12), (-3,-12) and (14,-5) lie on a circle with centre (2,0).
Plz help
Thnx in advanc
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