Mathematics: Post your doubts here!

[NIM]

hey guys, does anyone knows how to convert non linear exponential graph into linear graph, only graph points are give, we have to find equation also??? Plz help, i'll b thankful to you... thnx in advance ..

 

[Jspake]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w10_qp_13.pdf
Please help me with no. 9 (b) (ii).. I really don't understand how it is solved in the marking scheme.
Thanks

 

[Iffat]

Help needed

2008 oct-nov p1:
q2

2009 may-jun p1:
q4(ii)

2009 oct-nov p12:
q9(iii)
q10(i)(c)

 

[Kumkum]

Help needed

2008 oct-nov p1:
q2

2009 may-jun p1:
q4(ii)

2009 oct-nov p12:
q9(iii)
q10(i)(c)

oct/nov 08
2. 1+sinx/cosx = cosx/1+sinx take common denominator
= [(1+sinx)^2 + (cos^2)x]/cosx(1+sinx)
= (1 + 2sinx + (sin^2)x + (cos^2)x)/cosx(1+sinx) here an identity needs to be used : (cos^2)x +(sin^2)x = 1, so (sin^2)x = 1 - (cos^2)x
= (1 + 2sinx + 1 - (cos^2)x + (cos^2)x )/ cosx(1+sinx) , the '(cos^2)x' cancels out
= 2 + 2sinx/cosx(1+sinx)
= [2(1 + sinx)]/cosx(1+sinx) , the '1+sinx' cancels out
= 2/cosx hence equal to right hand side
hope you understood

 

[Alice123]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w12_qp_61.pdf
Pls explain 5ii
https://www.xtremepapers.com/community/members/syed1995.17088/
https://www.xtremepapers.com/community/members/dug.23386/
thanks in advance

 

[syed1995]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_61.pdf
Pls explain 5ii
https://www.xtremepapers.com/community/members/syed1995.17088/
https://www.xtremepapers.com/community/members/dug.23386/
thanks in advance

use @withusername like "@Dug" to tag.

This question is just logic based.

Profit If more than 1 fail to work = -480$ (Since company gets no money and that's the price of the fireworks) Probability = 0.264 (part i)
Profit If 1 or less than 1 fail to work = 4500 - 480 = 4020 ----- Probability = (1-0.264=0.736)

Expected Profit = (0.264*-480) + (0.736*4020)
=2832 .. or 2830 (3sf)

 

[syed1995]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_13.pdf
Please help me with no. 9 (b) (ii).. I really don't understand how it is solved in the marking scheme.
Thanks

Okay I don't understand it either.. I don't understand the question correctly but I will try anyway..

a= 100 d = -5
Sm=S(m+1)

Sm=n(2a-(n-1)d)/2
Sm=m(2(100)+5(m-1)/2
Sm=m(200+5m-5)/2
Sm=(195m+5m^2)/2

S(m+1)= m+1/2 * (2(100)+5(m+1-1))
S(m+1)= m+1 /2 * 200+5m
S(m+1)= (200m + 200 +5m^2+5m)/2

Sm=Sm+1
195m+5m^2=205m+200+5m^2
10m=200
m=20

Is that the correct answer?

 

[Alice123]

use @withusername like "@Dug" to tag.

This question is just logic based.

Profit If more than 1 fail to work = -480$ (Since company gets no money and that's the price of the fireworks) Probability = 0.264 (part i)
Profit If 1 or less than 1 fail to work = 4500 - 480 = 4020 ----- Probability = (1-0.264=0.736)

Expected Profit = (0.264*-480) + (0.736*4020)
=2832 .. or 2830 (3sf)

dint knw dat b4 syed1995
Anyways thanks

 

[parthrocks]

Hello syed1995 or anyone else please help me with this
these are sums of simple and compund interest but I am not getting it accurately...help me

 

[parthrocks]

this one too
syed1995

 

[parthrocks]

daredevil
this one is for you
plz asap

 

[parthrocks]

daredevil

 

[parthrocks]

anyone last one

 

[syed1995]

this one too
syed1995

sorry dude .. no idea about these questions .. i remember doing SI in O levels (No CI at all) but don't remember it that well to solve your question..

 

[daredevil]

Maths
Q 5 may june 2011 p11
Plz solve the second part for me

Q7 part ii

Q11 part iv

Pleaase solve...

 

[daredevil]

Ya

anyone last one

yaar sorry i dont know how to do compound interest.
I = PRT/100
Compound interest ka b formula le k uss mein values put ker k fekh lo difference ka expression bna k.

 

[daredevil]

daredevil

In q 6 calculate the interest by the PRT/100 formula and then add the principle to the interest to get the total amount to be paid after four years. That would be interest + original amount

 

[daredevil]

anyone last one

690 = I + P
I = 690 - P

690-P = R*3*X/100

Make a similar expression for 750 and then make a common subject in both equations and equate them.

 

[Jspake]

Okay I don't understand it either.. I don't understand the question correctly but I will try anyway..

a= 100 d = -5
Sm=S(m+1)

Sm=n(2a-(n-1)d)/2
Sm=m(2(100)+5(m-1)/2
Sm=m(200+5m-5)/2
Sm=(195m+5m^2)/2

S(m+1)= m+1/2 * (2(100)+5(m+1-1))
S(m+1)= m+1 /2 * 200+5m
S(m+1)= (200m + 200 +5m^2+5m)/2

Sm=Sm+1
195m+5m^2=205m+200+5m^2
10m=200
m=20

Is that the correct answer?

Damn.. that seemed pretty easy huh.

Its the correct answer.. thanks a lot!

 

[parthrocks]

690 = I + P
I = 690 - P

690-P = R*3*X/100

Make a similar expression for 750 and then make a common subject in both equations and equate them.

yes true!thanks and ya no problem syed1995
and daredevil attach the paper if possible i can help you