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Mathematics: Post your doubts here!

NIM

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hey guys, does anyone knows how to convert non linear exponential graph into linear graph, only graph points are give, we have to find equation also??? Plz help, i'll b thankful to you... thnx in advance :)..
 
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Help needed

2008 oct-nov p1:
q2

2009 may-jun p1:
q4(ii)

2009 oct-nov p12:
q9(iii)
q10(i)(c)
 
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Help needed

2008 oct-nov p1:
q2

2009 may-jun p1:
q4(ii)

2009 oct-nov p12:
q9(iii)
q10(i)(c)
oct/nov 08
2. 1+sinx/cosx = cosx/1+sinx take common denominator
= [(1+sinx)^2 + (cos^2)x]/cosx(1+sinx)
= (1 + 2sinx + (sin^2)x + (cos^2)x)/cosx(1+sinx) here an identity needs to be used : (cos^2)x +(sin^2)x = 1, so (sin^2)x = 1 - (cos^2)x
= (1 + 2sinx + 1 - (cos^2)x + (cos^2)x )/ cosx(1+sinx) , the '(cos^2)x' cancels out
= 2 + 2sinx/cosx(1+sinx)
= [2(1 + sinx)]/cosx(1+sinx) , the '1+sinx' cancels out
= 2/cosx hence equal to right hand side
hope you understood :)
 
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use @withusername like "@Dug" to tag.

This question is just logic based.

Profit If more than 1 fail to work = -480$ (Since company gets no money and that's the price of the fireworks) Probability = 0.264 (part i)
Profit If 1 or less than 1 fail to work = 4500 - 480 = 4020 ----- Probability = (1-0.264=0.736)

Expected Profit = (0.264*-480) + (0.736*4020)
=2832 .. or 2830 (3sf)
 
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http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_13.pdf
Please help me with no. 9 (b) (ii).. I really don't understand how it is solved in the marking scheme.
Thanks

Okay I don't understand it either.. I don't understand the question correctly but I will try anyway..

a= 100 d = -5
Sm=S(m+1)

Sm=n(2a-(n-1)d)/2
Sm=m(2(100)+5(m-1)/2
Sm=m(200+5m-5)/2
Sm=(195m+5m^2)/2

S(m+1)= m+1/2 * (2(100)+5(m+1-1))
S(m+1)= m+1 /2 * 200+5m
S(m+1)= (200m + 200 +5m^2+5m)/2

Sm=Sm+1
195m+5m^2=205m+200+5m^2
10m=200
m=20

Is that the correct answer?
 
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use @withusername like "@Dug" to tag.

This question is just logic based.

Profit If more than 1 fail to work = -480$ (Since company gets no money and that's the price of the fireworks) Probability = 0.264 (part i)
Profit If 1 or less than 1 fail to work = 4500 - 480 = 4020 ----- Probability = (1-0.264=0.736)

Expected Profit = (0.264*-480) + (0.736*4020)
=2832 .. or 2830 (3sf)
dint knw dat b4 syed1995 ;)
Anyways thanks
 
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Hello syed1995 or anyone else please help me with this
these are sums of simple and compund interest but I am not getting it accurately...help me
 

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Maths
Q 5 may june 2011 p11
Plz solve the second part for me

Q7 part ii

Q11 part iv

Pleaase solve...
 
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Okay I don't understand it either.. I don't understand the question correctly but I will try anyway..

a= 100 d = -5
Sm=S(m+1)

Sm=n(2a-(n-1)d)/2
Sm=m(2(100)+5(m-1)/2
Sm=m(200+5m-5)/2
Sm=(195m+5m^2)/2

S(m+1)= m+1/2 * (2(100)+5(m+1-1))
S(m+1)= m+1 /2 * 200+5m
S(m+1)= (200m + 200 +5m^2+5m)/2

Sm=Sm+1
195m+5m^2=205m+200+5m^2
10m=200
m=20

Is that the correct answer?
Damn.. that seemed pretty easy huh.

Its the correct answer.. thanks a lot!
 
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