• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Mathematics: Post your doubts here!

Messages
2,703
Reaction score
3,939
Points
273
i think using radian is not mandatory but u can use it as a safeguard . ask someone else as i am not sure upon this point
 
Messages
84
Reaction score
178
Points
43
:unsure: Guys till how many significant figures should we round our answers in the paper tomorrow ..!! pleasse..quick.:confused:
3 s.f

teach me this !
f(x)=4-sinx
- find the set of values of k for which the equation f(x)=k has no solution


my xam is just 4 hrs away o_O
 
Messages
17
Reaction score
5
Points
13
is
well in 6i) cos(x/2 + pie/6) =1
cos-1(1)=x/2 +pie/6
0=x\2 +pie/6
pie/3 =x
6ii f(g)= 1 hence sub
cosx/2 +pie/6 =1
cosx/2 =1-pie/6
cosx= 0.4764*2
cosx=0. 9528
x=0.31 and for the negative value we have to take x= -0.31
x=+-0.31
isn't the answer to the first part minus pie/3.
Can you recheck it again,please?
 
Messages
435
Reaction score
238
Points
53
ymUBq.png
Thankyouuuu :D
 
Messages
192
Reaction score
103
Points
53
i think using radian is not mandatory but u can use it as a safeguard . ask someone else as i am not sure upon this point

It's mandatory if the domain is given in radians... like 0 < x < pi. It clearly says in the ms, must be in radian.
1.5 hrs left for my exam, terrified here.
 
Messages
192
Reaction score
103
Points
53
I got it...
The limits of the graph of cos^2x are 0 --> 1
multiply both sides by -4
0 ---> -4 ,,,, since 0 is greater than -4 u flip it
-4 ----> 0
add 3
- 1 ---> 3
 
Top