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3 s.fGuys till how many significant figures should we round our answers in the paper tomorrow ..!! pleasse..quick.
isn't the answer to the first part minus pie/3.well in 6i) cos(x/2 + pie/6) =1
cos-1(1)=x/2 +pie/6
0=x\2 +pie/6
pie/3 =x
6ii f(g)= 1 hence sub
cosx/2 +pie/6 =1
cosx/2 =1-pie/6
cosx= 0.4764*2
cosx=0. 9528
x=0.31 and for the negative value we have to take x= -0.31
x=+-0.31
is
isn't the answer to the first part minus pie/3.
Can you recheck it again,please?
you sure this is the full question3 s.f
teach me this !
f(x)=4-sinx
- find the set of values of k for which the equation f(x)=k has no solution
my xam is just 4 hrs away
Thankyouuuu
Me too. Although i hate stats, especially permuations and combinations.so me u daredevil asd mustafamotani asd and syed will be there to answer queries
all of us hate it
i think using radian is not mandatory but u can use it as a safeguard . ask someone else as i am not sure upon this point
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s11_qp_12.pdfPhyZac solved this question before, search this thread for it.
pm me ur numberPhyZac solved this question before, search this thread for it.
If n is 10 than the answer will be 360/10=36 and for the range within 360 you can get further values e.g 36 +- 360 where n can be 1,2,3,4......
same hereI couldn't solve 9 i (a) when i tried to solve this paper before.
But 9 i (b) is easy... just equate it to 1 and solve.
could u solve my questionn
If n is 10 than the answer will be 360/10=36 and for the range within 360 you can get further values e.g 36 +- 360 where n can be 1,2,3,4......
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