• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Mathematics: Post your doubts here!

Anika Raisa

Anika Raisa

Messages
243
Reaction score
198
Points
43
Sanis said:
help guys in solving this .. (2x-1)ln5=ln2 + xln3 .. i have difficulities in this sort of questions
Click to expand...


ignore ma previous post!
I cud do it... dnt knw hw it came to me now but here it is:
The solution is given by:


(2x-1)ln5=ln2+xln3
=>2xln5-ln5=ln2+xln3
=> x(2ln5-ln3)=ln2+ln5
=> x=ln10 divided by ln25/3
=>x=1.086

formula used:

lna+lnblna−lnbalnb=lnab=lnab=lnba​





Golden rule:One trick while doing algebra always expand or simplify as much as u cn! n ys u gt it!

Uff dat was quiet challenging!(Btwn i dnt knw if the answer is ryt!)
Hope it helped! :)


​
 
Sanis

Sanis

Messages
65
Reaction score
12
Points
18
Anika Raisa said:
ignore ma previous post!
I cud do it... dnt knw hw it came to me now but here it is:
The solution is given by:


(2x-1)ln5=ln2+xln3
=> x(2ln5-ln3)=ln2+ln5
=> x=ln10ln253

formula used:

lna+lnblna−lnbalnb=lnab=lnab=lnba​





Golden rule:One trick while doing algebra always expand or simplify as much as u cn! n ys u gt it!

Uff dat was quiet challenging!(Btwn i dnt knw if the answer is ryt!)
Hope it helped! :)
Click to expand...
thanks alot :D u did help me
 
Sanis

Sanis

Messages
65
Reaction score
12
Points
18
Anika Raisa said:
ignore ma previous post!
I cud do it... dnt knw hw it came to me now but here it is:
The solution is given by:


(2x-1)ln5=ln2+xln3
=> x(2ln5-ln3)=ln2+ln5
=> x=ln10ln253

formula used:

lna+lnblna−lnbalnb=lnab=lnab=lnba​





Golden rule:One trick while doing algebra always expand or simplify as much as u cn! n ys u gt it!

Uff dat was quiet challenging!(Btwn i dnt knw if the answer is ryt!)
Hope it helped! :)
Click to expand...
thanks alot :D u did help me
 
Sanis

Sanis

Messages
65
Reaction score
12
Points
18
Anika Raisa said:
ignore ma previous post!
I cud do it... dnt knw hw it came to me now but here it is:
The solution is given by:


(2x-1)ln5=ln2+xln3
=> x(2ln5-ln3)=ln2+ln5
=> x=ln10ln253

formula used:

lna+lnblna−lnbalnb=lnab=lnab=lnba​





Golden rule:One trick while doing algebra always expand or simplify as much as u cn! n ys u gt it!

Uff dat was quiet challenging!(Btwn i dnt knw if the answer is ryt!)
Hope it helped! :)
Click to expand...
thanks alot :D u did help me
 
Anika Raisa

Anika Raisa

Messages
243
Reaction score
198
Points
43
Just visiting said:
I need your help guys in Question 6 Part ii
BTW this is may 2012
Click to expand...

I will give u the general points:
  • Differentiate the equation of the curve this is the gradient of the curve
  • Gradient of curve n line should equal if line is tangent to curve!
    (Equation of line: y=mx+c; m=gradient of line)
  • Or equations n then write b^2-4ac=0 (BEST METHOD!)
  • n knw u got k!
  • Use this value of k and write down the equation of both line n curve replacing k with its value.
  • now equate both the equations n get the value of x
  • then place this value of x in either equation of line or curve n you will have the value of y!
  • this value of x n y r the co ordinate of the point of intersection of tangent n curve
  • As here the co ordinate is asked remember to write in the format (x,y).
  • Follow the steps n u wil find the ans!
Hope it helped! :)
 
Esme

Esme

Messages
681
Reaction score
438
Points
73
Anika Raisa

Anika Raisa

Messages
243
Reaction score
198
Points
43
iKhaled said:
hey can someone pls show me a sketch of how to find the max value of arg z in this question 7(iii) i really wanna see a sketch not just word explanation..thanks a lot !!

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w03_qp_3.pdf
Click to expand...

Esme said:
I had a doubt in a similar question in another paper. I don't know how we find the max value or arg z. I hope someone can explain
Click to expand...


If u r not clear by the diagram only:
  • I have used tangent theorem
  • first i found out the angle uOX
  • then multiplied by two!
  • Well i did it dis way cz u c both OM n OX r tangent to d circle n so Ou bisects the angle MOX.
One question on ma part: If min arg ws to be found which angle would it hv been?wud it hv bn angle uOX?

n guyzz cn u help me wid the sum here i nid help here desperately!:
https://www.xtremepapers.com/community/threads/pure-mathematics-3-help.25895/

Thank u!N hope i was helpful!:)
 

Attachments

  • w03 p3 7 iii.JPG
    w03 p3 7 iii.JPG
    14.3 KB · Views: 15
Esme

Esme

Messages
681
Reaction score
438
Points
73
This is May June 10 P43. I kind of did this but can some one explain Q7 i) and ii)
Screenshot_2013-05-11-23-26-20.png

Here's the marking scheme:
Screenshot_2013-05-11-23-32-04.png
 

Attachments

  • Screenshot_2013-05-11-23-26-20.png
    Screenshot_2013-05-11-23-26-20.png
    167.6 KB · Views: 4
Esme

Esme

Messages
681
Reaction score
438
Points
73
Anika Raisa said:
If u r not clear by the diagram only:
  • I have used tangent theorem
  • first i found out the angle uOX
  • then multiplied by two!
  • Well i did it dis way cz u c both OM n OX r tangent to d circle n so Ou bisects the angle MOX.
One question on ma part: If min arg ws to be found which angle would it hv been?wud it hv bn angle uOX?


n guyzz cn u help me wid the sum here i nid help here desperately!:
https://www.xtremepapers.com/community/threads/pure-mathematics-3-help.25895/

Thank u!N hope i was helpful!:)
Click to expand...

Erm thanks I'll get to argand diagrams when my mechanics paper is over :)
 
You must log in or register to reply here.
Top