- Messages
- 172
- Reaction score
- 147
- Points
- 53
okay in d ( i ) we found the molecular formula as SiCl3... now in d ii the first Mr is 133 that is SiCl3 cuz (28+35+35+35=133)... now we have 247... let's see 247-133=114, we knw the formula of 133, find the formula of 114 which is SiCl2O (28+35+35+16=114) ,add both formulas of 133 and 114 i.e SiCl3 + SiCl2O = Si2Cl5O(Cl 3Si-O-SiCl 2 )Asalamo Alaikum everyone!
Can anyone please help me with this A2 question:-
Q 3 part d(ii) of this paper?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s10_qp_42.pdf
do the same for 263.. 263 - 247 = 16,meaning only O is added hence add Si2Cl5O + O= Si2Cl5O2 (.Cl 3Si-O-SiCl 2-O)
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