can someone solve q2 http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w12_qp_32.pdf
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did anyone help you?i had some ambiguity in below quest:
1) P(Z>a)=0.8888 , a is negativ,
1-fi(-a)=o.8888
1-[1-fi(a) ]=o.8888
the other solution of quest i found:
2)p(z<t)=0.25, t is negativ
fi(-t)=0.25
1-fi(t)=0.25..
can anyone tell me this difference and concept how to solve such type of quest plzzz![]()
its 2 + 2^(1/2)?Alright... ii) part please ?
THANX MAN you Are A Big Help In This Crucial Tym INSHALLAH ALLAH will Reward U(3-λ)i + (-2+2λ)j + (1+λ)k = (4 +µa)i + (4 +µb)j + (2-µ)k
comparing coefficients of k
(1+λ) = (2-µ)
λ = 1 - µ
comparing coefficients of i
(3-λ) = (4 +µa)
3 -1 + µ = 4 + µa
µ = 2/(1-a)
comparing coefficients of j
(-2+2λ) = (4 +µb)
-2 + 2 - 2µ = 4 + µb
0 = 4 + µ(2+b)
0 = 4 + (4+2b)/(1-a)
2a-b = 4
its 2 + 2^(1/2)?
thanx for the prayer..THANX MAN you Are A Big Help In This Crucial Tym INSHALLAH ALLAH will Reward U![]()
wait ..
Alright... ii) part please ?
Thank you so much.These might help, but do as many past paper questions on these topics as you can.
And most importantly pray to Allah, insha'Allah you will get it.![]()
Sorrry for the delay .. am not good at paint ..![]()
It's ok. Chill !
This really helped! Got it now!Thanks a lot
no need to say thanx again and again or I wil have to say "anytime" again and again ..![]()
Esme Can you plz help me with q.4 of this paper.: http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_32.pdf![]()
u dont have to keep sayin anytime everytime...just like the post dudeno need to say thanx again and again or I wil have to say "anytime" again and again ..![]()
really ?? .. ohkay..u dont have to keep sayin anytime everytime...just like the post dudeliking it is like sayin u welcome
![]()
can someone solve q2 http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w12_qp_32.pdfas far as i can comprehend you would be having difficult in integrating
cos(2x)/sin(2x) dx
u see differential of sin(2x) is 2cos(2x) ...
to get 2 cos(2x) in numerator just multiply the integral with 2/2
u shall get 1/2 S 2 cos(2x)/sin(2x) ( S denotes integral sign)
now u can integrate using integration by recognition.. it will become
1/2 ln (sin(2x))
i got it thanksits logarithm question
substitute 5^x by a
yu shall get
a/5 = a - 5 (if yu dont get this step .. tell me)
a = 5a - 25
a =25/4
now
5^x = 25 /4 (apply logs to both sides)
x log (5) = log (25/4)
x = 1.14
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