Mathematics: Post your doubts here!

[SararaIH]

yah ..

Another load to put on my shoulders

Thanks for your help though!

 

[Anika Raisa]

OMG, someone please help me out in question 2- http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_w12_qp_32.pdf

Hope this helps!!!

 

[SararaIH]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s12_qp_32.pdf
I need help with the full working of Q8i

 

[Esme]

OMG, someone please help me out in question 2- http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_w12_qp_32.pdf

5^(x-1) = 5^x - 5
(5^x)/5 = 5^x - 5
Take 5^x = u
u/5 = u - 5
u= 5u - 25
u=25/4

5^x = 25/4
And so x = 1.14

 

[Silent Hunter]

How to continue further from here ? : (may be something very basic...... but its not coming into ma mind right now :\ )



its q4 of http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_33.pdf

Rutzaba
Esme
applepie1996

or anyone ?

 

[Rutzaba]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_qp_31.pdf

Need help with question 9



Tan(x/2) integrates to -ln(cos(x/2))

http://i1275.photobucket.com/albums/y444/Rutzaba/maths_zps139585a6.png

 

[Rutzaba]

How to continue further from here ? : (may be something very basic...... but its not coming into ma mind right now :\ )

View attachment 26601

its q4 of http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_33.pdf

Rutzaba
Esme
applepie1996

or anyone ?

=

How to continue further from here ? : (may be something very basic...... but its not coming into ma mind right now :\ )

View attachment 26601

its q4 of http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_33.pdf

Rutzaba
Esme
applepie1996

or anyone ?

convert everything to ln
lny= ln(x^2 +4)^3 +ln32 -ln4^3
got it?

 

[Silent Hunter]

=
convert everything to ln
lny= ln(x^2 +4)^3 +ln32 -ln4^3
got it?

yeah tried that : but the MS says something else : http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w12_ms_33.pdf

 

[Rutzaba]

yeah tried that : but the MS says something else : http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_ms_33.pdf

han na
tou wo is ke bad ka step hai..
in log jub minus hota hai to divide hota hai...
han ye question i remember its wrong in the ms

 

[LMGD33]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_qp_32.pdf
I need help with the full working of Q8i

Sorry i skipped the part where i got the limits.. you just substitute x = 5 and x = 2 in u = sqrt (6- x) to get 2 and 1 respectively, but since they asked us to flip the limits, we multiply the entire integrand by -1 thus getting rid of the - 10 u !!
Good luck!

 

[VinnCh]

Hello , is there any kind soul out there who can help me with Q7 (ii) ? I don't know how to solve it. 9709_s11_qp_32

 

[LMGD33]

Hello , is there any kind soul out there who can help me with Q7 (ii) ? I don't know how to solve it. 9709_s11_qp_32

Hello. I solved it long ago, and i'm checking my copybook, I hope you solved part (i) correctly.. when you sketch it, you have the angle and the opposite side is (10/a^2 +4) and the adjacent side is (5a/a^2 + 4) so to find the tan of the angle which they provided, you need to write tan(3pi/4) = opp/adj
This gives : tan (3pi/4) = 10/5a
[shift] tan(3pi/4) = 10/5a
-1 = 10/5a
a= -2
Good luck!!

 

[Anika Raisa]

Solutions to P3 paper 33 year may/june 2012!

 

[applepie1996]

han na
tou wo is ke bad ka step hai..
in log jub minus hota hai to divide hota hai...
han ye question i remember its wrong in the ms

explaining math in urdu
hahaha xD just makes it more complicated

 

[LMGD33]

Solutions to P3 paper 33 year may/june 2012!

THANK YOUUUU!!! OMG This is wonderful! Inshallah will help me tomorrow God bless you!

 

[SararaIH]

Sorry i skipped the part where i got the limits.. you just substitute x = 5 and x = 2 in u = sqrt (6- x) to get 2 and 1 respectively, but since they asked us to flip the limits, we multiply the entire integrand by -1 thus getting rid of the - 10 u !!
Good luck!

So after we integrate this completely, we still have to multiply the -1 at the end, right?

 

[Anika Raisa]

THANK YOUUUU!!! OMG This is wonderful! Inshallah will help me tomorrow God bless you!

Remember me in your prayers!!!

 

[SararaIH]

Solutions to P3 paper 33 year may/june 2012!

I don't have WINRAR so I can't open it :'(

 

[VinnCh]

Hello. I solved it long ago, and i'm checking my copybook, I hope you solved part (i) correctly.. when you sketch it, you have the angle and the opposite side is (10/a^2 +4) and the adjacent side is (5a/a^2 + 4) so to find the tan of the angle which they provided, you need to write tan(3pi/4) = opp/adj
This gives : tan (3pi/4) = 10/5a
[shift] tan(3pi/4) = 10/5a
-1 = 10/5a
a= -2
Good luck!!

Thank youu!! I confused the tangent formula with the distance formula. I must be really sleepy now. But thanks to you I got it now! =)

 

[VinnCh]

I don't have WINRAR so I can't open it :'(

You can get the free trial version here, its a pretty handy tool so its good to have it in your PC. =) http://www.rarlab.com/download.htm