• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Mathematics: Post your doubts here!

Messages
681
Reaction score
438
Points
73
yes and i got A= 1/1800 and B = 1/1800 y does the mark scheme says A= 2 and B= 2 :S

Ignore the ms :/
Yeah that's what I got too. Now integrate it just like you would normally do.
After integration you get
1/1800(ln|N|) - 1/1800(ln|1800-N| = t/3600 + c
Use t=0, N=300 to find c
c=1/1800(ln|1/5|)

And then solve it to find N in terms of t
 
Messages
870
Reaction score
374
Points
73
Ignore the ms :/
Yeah that's what I got too. Now integrate it just like you would normally do.
After integration you get
1/1800(ln|N|) - 1/1800(ln|1800-N| = t/3600 + c
Use t=0, N=300 to find c
c=1/1800(ln|1/5|)

And then solve it to find N in terms of t
yeah thats what i got the first time but when i looked through the mark scheme i saw A= 2 and B=2 then i was :O so is our answers considered correct?
 
Messages
681
Reaction score
1,731
Points
153
thank u pls do tell me the answer when u get it
Oh very very sorry, when i read your post, i thought you got 3√2 / 2 and MS got 3√2

Anyway, see, check this sketch and try finding the blue line.
 

Attachments

  • s.PNG
    s.PNG
    2.4 KB · Views: 9
Messages
681
Reaction score
438
Points
73
yeah thats what i got the first time but when i looked through the mark scheme i saw A= 2 and B=2 then i was :O so is our answers considered correct?

The final answer that I got matches the marking scheme, only the steps in between were different
 
Messages
599
Reaction score
3,840
Points
253
A < |z| < B
C < Arg(Z) < D

Minimum and max values for these? what formula to be used?

Secondly, when we are asked to take sq root of a complex number and from result we've to predict other root, do we multiply the root we get by -1? or take its u*?
Thirdly, when question is mixed with polynomials, how to get other root? eg. w12 qp32 ?
 
Messages
681
Reaction score
1,731
Points
153
A < |z| < B
C < Arg(Z) < D

Minimum and max values for these? what formula to be used?

Secondly, when we are asked to take sq root of a complex number and from result we've to predict other root, do we multiply the root we get by -1? or take its u*?
Thirdly, when question is mixed with polynomials, how to get other root? eg. w12 qp32 ?
For secondly
take its conjugate.
 
Messages
681
Reaction score
438
Points
73
A < |z| < B
C < Arg(Z) < D

Minimum and max values for these? what formula to be used?

Secondly, when we are asked to take sq root of a complex number and from result we've to predict other root, do we multiply the root we get by -1? or take its u*?
Thirdly, when question is mixed with polynomials, how to get other root? eg. w12 qp32 ?

For thirdly:
If you're given one complex root, the other will be it's conjugate.
 
Messages
681
Reaction score
438
Points
73
A < |z| < B
C < Arg(Z) < D

Minimum and max values for these? what formula to be used?

Secondly, when we are asked to take sq root of a complex number and from result we've to predict other root, do we multiply the root we get by -1? or take its u*?
Thirdly, when question is mixed with polynomials, how to get other root? eg. w12 qp32 ?

As for your first doubt. There's no specific formula. Depends on the question..
 
Messages
681
Reaction score
438
Points
73
7(ii) and (iii), of http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s10_qp_31.pdf

Detail on 7 (ii) i can make out |z-u|<1 will be circle with radius 1 n centre 2,2 but cant make out the other inequality!!!
Please help!

Esme or any1?

Mark the point 1 and then mark another point i
Join these two and make their perpendicular bisector

And then shade the area inside your circle and below the perpendicular bisector. i.e. the area closer to the point 1
 
Top