Physics unit 1 6PH01 discussion :)

[e1f123]

The paper was dead easy

dont get too cocky son

 

[e1f123]

It was T=W/3sintheta

thats correct

 

[svenas]

It was T=W/3sintheta

i got 3W/smthn

 

[svenas]

thats correct

mcq was D?

 

[ALevel96]

3Tsintheta=mg

Therefore T=mg/3sintheta

 

[e1f123]

DOES ANY ONE HAVE THE PHILLIP ALLAN UNIT GUIDE UNIT 2 FOR PHYSICS PLEASE SEND ME A LINK FOR THAT IN PDF I REALLY NEED IT PLEASE

 

[MarvinM]

Also about the question with the graph and the stupid woman using that stupid sports machine. How could you find the work done using the graph and what could we say about the overestimate on the spreadsheet?

 

[ALevel96]

I put the area under the graph
And the lines formed trapezia that went above the curve :S not sure tho anyone else put this?

 

[e1f123]

Also about the question with the graph and the stupid woman using that stupid sports machine. How could you find the work done using the graph and what could we say about the overestimate on the spreadsheet?

i put down the area under the curve

 

[Cell_ar]

Wasnt it W/3costheta? the question said it was theta to the veritcal not horizontal

 

[Zahidur]

It should be W/3costheta because the angle was to the vertical and not the horizontal like most question. For the carbon-dioxide question the difference in emission was 2.2kg right?

 

[MarvinM]

i put down the area under the curve

That's correct , what about the mean and spreadsheet and the overestimate?

 

[MarvinM]

It should be W/3costheta because the angle was to the vertical and not the horizontal like most question. For the carbon-dioxide question the difference in emission was 2.2kg right?

You sure it's not 3W/costheta ? The carbon dioxide one was 0,78

 

[svenas]

You sure it's not 3W/costheta ? The carbon dioxide one was 0,78

i got like u 3W/cos

 

[e1f123]

DOES ANY ONE HAVE THE PHILLIP ALLAN UNIT GUIDE UNIT 2 FOR PHYSICS PLEASE SEND ME A LINK FOR THAT IN PDF I REALLY NEED IT PLEASE​

 

[shalala]

Wasnt it W/3costheta? the question said it was theta to the veritcal not horizontal

I am totally agreeing with you on this one! it was cos!! a HUNDRED PERCENT sure

 

[shalala]

That's correct , what about the mean and spreadsheet and the overestimate?

for overestimate i saide he didn't multiply by a half (1/2)

it was a guesss :S

 

[Zahidur]

Overestimate because the formula the student used was wrong. The student forgot to add '0.5' to his calculations.

 

[svenas]

Overestimate because the formula the student used was wrong. The student forgot to add '0.5' to his calculations.

what u expect the boundary to beeee?

 

[ALevel96]

You sure it's not 3W/costheta ? The carbon dioxide one was 0,78

Yes finally someone got something similar to me on the CO2 question!

I got 0.75 probably give you a range of values since you have to read off the graph