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P1 MCQ's preparation thread for chemistry ONLY!!!!

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Can anybody explain this to me? It's q1 in May June 2004..

1 Which of these samples of gas contains the same number of atoms as 1g of hydrogen (Mr: H2 = 2)?
A) 22g of carbon dioxide (Mr: CO2, 44)
B) 8g of methane (Mr: CH4, 16)
C) 20g of neon (Mr: Ne, 20)
D) 8g of ozone (Mr: O3, 48)

Aren't A and B the same answer?
 
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Can anybody explain this to me? It's q1 in May June 2004..

1 Which of these samples of gas contains the same number of atoms as 1g of hydrogen (Mr: H2 = 2)?
A) 22g of carbon dioxide (Mr: CO2, 44)
B) 8g of methane (Mr: CH4, 16)
C) 20g of neon (Mr: Ne, 20)
D) 8g of ozone (Mr: O3, 48)

Aren't A and B the same answer?

i am also confused wid dis question
plz somebody enlighten us
 
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.is t
mcq 2) B is not the ans cz p=9, n=19-9=10 nd e=10 nd the qts says all shud b different...
mcq 10) u need to check using electronegativities...
mcq 33) 1 is correct h2so4 is a strong acid nd will release high conc. of H+ ions....SO4 ^2- ions r not in high conc.b/c the HSO4- is a weak acid...so 2 is incorrect in dis way u dont need to think of 3...so D is correct...
as we go across a period electronrgativity increases. Down a grp electronegativity decreases.is this correct??
 
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i am also confused wid dis question
plz somebody enlighten us

The question says the mass of HYDROGEN ATOMS, we take the mr to be 1 and the mass is 1g which give us 1 mole.
Since Ne has mr of 20, and the mass is 20, the moles will be equal to 1. the no of atoms are thus same to that of 1 g of HYDROGEN ATOMS.
Hope you understand :)
 
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h
Q21- Substitute n by numbers 1 to 4. then find all isomers. There will be 7.
Q37- In 2 there will be only one ketone and one acid as there is one primary and one secondary C atom. In 3 a ketone and a dibasic acid will b produced. Only one has 2 secondary C atoms so it will produce 2 ketones.
Q39- H2SO4 will dehydrate the compounds. 1 on dehydration will produce an alkene which reacts with KMnO4. 2 also forms an alkene. 3 is an acid so it wont react with H2SO4.

in Q2 how 7 please explain :)
 
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thanks.. bt i thought that aldehydes can only b made by using K2Cr207?!

Yes aldehydes are made but you can say that they are the initial products of oxidation of primary alcohol..the final product is carboxylic acid :)
 
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if aldehyde is reacted with cold kmno4 wat will b the product?

when aldehydes are oxidised using acidified KMNO4, carboxylic acids are produced and when oxidised using alkaline KMNO4, salt of carboxylic acids are produced.
 
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when aldehydes are oxidised using acidified KMNO4, carboxylic acids are produced and when oxidised using alkaline KMNO4, salt of carboxylic acids are produced.

Will not the condition effect the product? i mean hot / cold oxidising agent?
 
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