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P1 MCQ's preparation thread for chemistry ONLY!!!!

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(5) HCl is polar and therefore, there are forces of attraction between H+ and Cl-.
Ideal gases do not have forces of attraction!

(15) The balanced equation is 2Ca(NO3)2 ----> 2CaO + 4NO2 + O2
No. of moles of Ca(NO3)2 = 8.2/164 = 0.05
The mole ratio of Ca(NO3)2 to Oxygen is 2 : 1. Hence, no of moles of O2 formed becomes 0.025
No. of moles = volume/molar volume
0.025 = x/24
x = 0.6 dm3 = 600 cm3

(16) Thermal stability of elements increase as you move down the group II. As you can see, Barium is the most thermally stable from the options.
Barytocalcite, BaCO3.CaCO3 will form C02 and CaO, and BaCo3 remains in the solution due to its high thermal stability. This reacts with HCl

(17)I'm not very sure of this.. but here's what I think:
A ligand is an ion that forms a dative bond. This means that it contains a lone pair of electrons. Ag+ ion has an incomplete outer shell which forms a dative bond with ammonia.

(20) Apart from the cis-trans isomers, the third one is (Cl2)C = C(H2). So the total becomes 3

(24) butan-2-ol gives two main products: CH2=CHCH2CH3 and CH3CH=CHCH3. But CH3CH=CHCH3 can form the cis-and trans isomers.
Hence, 3 products are formed.

Hope that helped :)
 
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(5) HCl is polar and therefore, there are forces of attraction between H+ and Cl-.
Ideal gases do not have forces of attraction!

(15) The balanced equation is 2Ca(NO3)2 ----> 2CaO + 4NO2 + O2
No. of moles of Ca(NO3)2 = 8.2/164 = 0.05
The mole ratio of Ca(NO3)2 to Oxygen is 2 : 1. Hence, no of moles of O2 formed becomes 0.025
No. of moles = volume/molar volume
0.025 = x/24
x = 0.6 dm3 = 600 cm3

(16) Thermal stability of elements increase as you move down the group II. As you can see, Barium is the most thermally stable from the options.
Barytocalcite, BaCO3.CaCO3 will form C02 and CaO, and BaCo3 remains in the solution due to its high thermal stability. This reacts with HCl

(17)I'm not very sure of this.. but here's what I think:
A ligand is an ion that forms a dative bond. This means that it contains a lone pair of electrons. Ag+ ion has an incomplete outer shell which forms a dative bond with ammonia.

(20) Apart from the cis-trans isomers, the third one is (Cl2)C = C(H2). So the total becomes 3

(24) butan-2-ol gives two main products: CH2=CHCH2CH3 and CH3CH=CHCH3. But CH3CH=CHCH3 can form the cis-and trans isomers.
Hence, 3 products are formed.

Hope that helped :)


thnx aloooooot :)
 
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http://papers.xtremepapers.com/CIE/... AS Level/Chemistry (9701)/9701_s12_qp_12.pdf .kindly also tell these qusetions.2(why not B),7(plz elaborate this one), 10,33.thanks alot!!!

mcq 2) B is not the ans cz p=9, n=19-9=10 nd e=10 nd the qts says all shud b different...
mcq 10) u need to check using electronegativities...
mcq 33) 1 is correct h2so4 is a strong acid nd will release high conc. of H+ ions....SO4 ^2- ions r not in high conc.b/c the HSO4- is a weak acid...so 2 is incorrect in dis way u dont need to think of 3...so D is correct...
 
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mcq 2: divide the secnd eq by 5 to make 10 Na ---> 2 Na...2 moles NaN3---> 1/5 mol of N2 + 3 moles of N2 (from first eq)
so 1 mol of NaN3 -----> x moles of N2
x= 3.2/ 2 = 1.6 mol of N2 hence B....
mcq 7) I2 +Cl2 ---> 2 ICl the value is + 14 now half of 14 cz in da secnd eq u hav 1 ICl + Cl2 ---> ICl3 hence (+14/2) - 88 = -81 so ans C...
mcq 13) u need to see electronegativity table it says berrylium has same electronegativity as aluminium...
mcq 18) CO (NH2)2 has CON2H4 ,NH4+ in ammonium hence left is CNO it must hav a -1 sign to make acompound wid NH4+....
HOPE U GOT THESE....:)
 
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mcq 2) B is not the ans cz p=9, n=19-9=10 nd e=10 nd the qts says all shud b different...
mcq 10) u need to check using electronegativities..
mcq 33) 1 is correct h2so4 is a strong acid nd will release high conc. of H+ ions....SO4 ^2- ions r not in high conc.b/c the HSO4- is a weak acid...so 2 is incorrect in dis way u dont need to think of 3...so D is correct...

In question 10 how will i know that electronegativity of cl will be less than CH3, in option b and c.thanks alot for rest!!
 
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mcq 2) B is not the ans cz p=9, n=19-9=10 nd e=10 nd the qts says all shud b different...
mcq 10) u need to check using electronegativities...
mcq 33) 1 is correct h2so4 is a strong acid nd will release high conc. of H+ ions....SO4 ^2- ions r not in high conc.b/c the HSO4- is a weak acid...so 2 is incorrect in dis way u dont need to think of 3...so D is correct...

what about question 7.kindly explain that to.thanks!
 
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mcq 2: divide the secnd eq by 5 to make 10 Na ---> 2 Na...2 moles NaN3---> 1/5 mol of N2 + 3 moles of N2 (from first eq)
so 1 mol of NaN3 -----> x moles of N2
x= 3.2/ 2 = 1.6 mol of N2 hence B....
mcq 7) I2 +Cl2 ---> 2 ICl the value is + 14 now half of 14 cz in da secnd eq u hav 1 ICl + Cl2 ---> ICl3 hence (+14/2) - 88 = -81 so ans C...
mcq 13) u need to see electronegativity table it says berrylium has same electronegativity as aluminium...
mcq 18) CO (NH2)2 has CON2H4 ,NH4+ in ammonium hence left is CNO it must hav a -1 sign to make acompound wid NH4+....
HOPE U GOT THESE....:)


yes i got it
thanks a lot :)
 
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