Physics: Post your doubts here!

[Tkp]

May june 11(12)-29,34,16,8

 

[Tkp]

May june 11(13)-27,14

 

[Tkp]

View attachment 28660

uncertainity should always be added and should be taken to 1sf
so 1.27-.83
and 0.02+0.01=0.03
so (0.03/.44)*100=6.8%=in 1sf its 7

 

[Tkp]

View attachment 28659

well what is the ans?d
if its d then stress =f/a
and the radius is1/4 and the area is 1/16
so f/1/16=16f
and the orginal 1s radius is 1/2 and area is 1/4 so stress is 4f so it increases to 4
and the strain=extension/original length
so diameter changes doesnt affect strain

 

[bogus]

put in values and you'll realise current increases ... its parallel combination remember!

Yaeh... okay thannks

 

[abrar]

Thank u soo much.....could u please explain these questions 2...
M j 2012 paper 11 question 12,18,23
M j 2012 paper 12 question 6,13,23,24,26,28,29,30.
May ALLAH bless u.

12) you need to know mechanics m1 for this method: 120g-t=120a and ( T stands for tension in rope which is constant)
t-80g=80a , add both equations t gets cancelled off and find a using g=10ms-2, use u=0 s=9m because at half way only the man's head is at the bottom of the barrel as acceleration is constant for both of them, find v using v^2=u^2+2as

q18) output energy / input energy
output is in power convert it into energy using p=E/t, pxt=E, and obviously input is 40Mj x 20

 

[Antalya]

I don't really have what you are searching for but I have the examinator's report. It includes all answers for June Paper 1 2002

Thank you so much, I owe you one

 

[haha101]

Amyone to solve these challenging, mind-blowing question?
View attachment 28655

Look . the wave p completes three complete cycles before meeting at point x . while Q completes 3,5 cycles . when you take the difference it is 3.5 - 3.o = 0.5 cycles which is Pi

 

[haha101]

View attachment 28656

Assume that one resistor is 2 ohms .
p=V2/R .
since voltage is same it will cancel out .
you will get :
resistance of series/ resistance of parallel
Rs=6
rp = 2/3
Divide n youll get the Ans .

 

[haha101]

View attachment 28657

Just the use of a basic principle .
Resistance = resistivity x length/Area.
Remember if length decreases then area increases . by the same factor .
Here the length is halved so the area will become twice of that as before .



For dia 1 : R1= l/A

For dia 2 :
R2=0.5l/2A

if we rearrange the eq for dia 1 then we get 4R2 = l/A

Substitute l/A to R1 : 4R2=R1

R1 = 8
4R2=8
R2=8/4 = 2 Ohms

Hope you got it

 

[haha101]

View attachment 28659

Is it D ?

 

[A star]

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_s09_qp_1.pdf Q15? working pls

 

[A*(a*)]

Is it D ?

I thought it would be D, but its C

 

[haha101]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_1.pdf Q15? working pls

Yeah tou hogaya

 

[TaffsAsLevel]

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Haha none are mind blowing I can do those, try my question june 2002 question 36. I dare ya

 

[TaffsAsLevel]

Amyone to solve these challenging, mind-blowing question?
View attachment 28655

Path difference is QX-PX which year is that? How can you get pi?

 

[TaffsAsLevel]

View attachment 28658

Haha this for A2 but it is easy just get mgh and divide by its respective masses and there bingo

 

[hope4thebest]

Help needed!

 

[TaffsAsLevel]

Question 36 nov 2002 this question is impossible

 

[TaffsAsLevel]

View attachment 28688

Help needed!

It is A, it should always be perpendicular to surface and arrow towards negative, but then the field is not uniform and closest means stronger field hence closer lines

Help me with nov 2002 question 36 please