Physics: Post your doubts here!

[hope4thebest]

It is A, it should always be perpendicular to surface and arrow towards negative, but then the field is not uniform and closest means stronger field hence closer lines

Help me with nov 2002 question 36 please

yes A is correct thanks

 

[hope4thebest]

It is A, it should always be perpendicular to surface and arrow towards negative, but then the field is not uniform and closest means stronger field hence closer lines

Help me with nov 2002 question 36 please

look as this is a parallel circuit...both terminals will have 2 V potential difference across them.Resistors have same value(5 ohm) so p.d will divide by 3 for each resistor that is 2/3 V.After passing 1st resistor in 1st series p.d remaining would be (2 - 2/3=4/3) at X. In 2nd series current passes through 2 resistors before coming to Y. P.d at Y would be (2 -2/3 -2/3= 2/3). So p.d between X and Y would be ( 4/3 - 2/3 = 2/3). A answer

 

[TaffsAsLevel]

look as this is a parallel circuit...both terminals will have 2 V potential difference across them.Resistors have same value(5 ohm) so p.d will divide by 3 for each resistor that is 2/3 V.After passing 1st resistor in 1st series p.d remaining would be (2 - 2/3=4/3) at X. In 2nd series current passes through 2 resistors before coming to Y. P.d at Y would be (2 -2/3 -2/3= 2/3). So p.d between X and Y would be ( 4/3 - 2/3 = 2/3). A answer

Thank you buddy

 

[white rose]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_1.pdf Q15? working pls

E=mgh
since the vessels are identical the height amd mass both will be half leading to....
m/2*h/2*g= mhg/4

 

[hope4thebest]

Thank you buddy

 

[Antalya]

View attachment 28657

Hey where did you get these questions from? They're pretty good

 

[Zsiddiqui]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w10_qp_12.pdf help in question numbers : 15, 25,26 and 33

 

[TaffsAsLevel]

Hey where did you get these questions from? They're pretty good

Check OCR they have way tougher questions, more mind twisting

 

[A*(a*)]

Hey where did you get these questions from? They're pretty good

Thats Cambridge Pre -U , another thing in CIE link, thats a level ahead of A level! I am doing it just for practice ,some of them are really harrrrrrrrrrd , but just for the sake of papers

 

[A*(a*)]

Hey where did you get these questions from? They're pretty good

http://papers.xtremepapers.com/CIE/Cambridge Pre-U/ physics section, only some of them are there :/

 

[Antalya]

Check OCR they have way tougher questions, more mind twisting

Tougher than CIE?

 

[Antalya]

http://papers.xtremepapers.com/CIE/Cambridge Pre-U/ physics section, only some of them are there :/

Thank you! This is really helping me practice. I'm sure you'll nail an A*!

 

[sara kamal]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w11_qp_11.pdf

please explain Q32,23,20.
I will be very thankful

 

[Yousif Mukkhtar]

Q9: i found this answer posted by someone else, so not taking any credits!
"initial momentum of the ball is 2mv before collision... if collision was perfectly elastic one, all the momentum would have been gained by the ball... and this would have made the change in the momentum equal to 4mv.. 2mv-(-2mv)... now it is given that collision is inelastic, it will lose some of its momentum to the wall.. so now change in momentum will be less than 4mv but cant be less than the initial momentum... so the answer is C.. i think you cannot verify the answer by the calculations..."
Q11:
The tension in the rope needs to balance out the weight of the student acting downwards, so since the total tension needs to be opposite and equal to the weight, Let tension in rope on left side be T1 and the tension on rope on right side T2 and :. Total tension = T1sino + T2sino
add them up... W= 2Tsino, rearrange to get T= W/ 2sino. Answer: B
Q14:
Weight of box on slope with inclination of 30 degrees, mgsino= 200*sin30 and this acts downwards along the slope and the frictional force also act downwards along the slope so...(200*sin30) + 150= 250
And since W=F*d, we have to find out the distance d along the slope, so hypotenuse...1.5/sin30
The forward force to maintain a steady speed is the frictional force plus the component of weight along slope
W= ((200*sin30) + 150)*(1.5/sin30 )
Answer: D
Hope this helps!

You helped me a lot. Thank you for the great help and may Allah shine you with all As this May june session

 

[Yousif Mukkhtar]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w11_qp_11.pdf

please explain Q32,23,20.
I will be very thankful

Q32:
Resultant force is zero as forces acting on Q and -Q are same in magnitude but opposite in directions. Now you can see that both forces form a couple which turns the rod anticlockwise.

Q23:
Both wires are of the same material which is steel so both Young modulus are exactly same. DImensions do not matter when materials are exactly same
Q20:
Formula for PE is mgh

Here E is the potential energy lost. So:
pe=mgh
E=mgx
g=E/mx and this happens in the right direction. If it is in the opposite direction pe is gained not lost!

 

[A*(a*)]

Thank you! This is really helping me practice. I'm sure you'll nail an A*!

thanks do pray for me, I just need your prayers

 

[Zsiddiqui]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w10_qp_12.pdf please help in question numbers : 15, 25,26 and 33. Thanks in advance

 

[A*(a*)]

Haha this for A2 but it is easy just get mgh and divide by its respective masses and there bingo

is it sth. related to A2? oh so i do not need to do it, han?

 

[Rahma Abdelrahman]

June 2012 P12 Q18..
Can anyone solve this?

 

[Warrior66]

You helped me alot. Thank you for the great help and may Allah shine you with all As this May june session

Jazaka'Allahum Khairan! A'ameen, and I pray the same and more for you!