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With cold, dilute KMnO4, the C=C bond turns into C(OH)-C(OH). With hot, concentrated, it turns into C=O and O=C.
But only 2 OH is formed
Edit: There is an OH group down HAHA, I got it now.
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With cold, dilute KMnO4, the C=C bond turns into C(OH)-C(OH). With hot, concentrated, it turns into C=O and O=C.
With cold, dilute KMnO4, the C=C bond turns into C(OH)-C(OH). With hot, concentrated, it turns into C=O and O=C.
"Question number 11 please
http://papers.xtremepapers.com/CIE/... AS Level/Chemistry (9701)/9701_s11_qp_12.pdf "
Its C aluminum carbide
Al4C3+12H2O------->4AL(OH)3+3CH4
CH4+2O2----->2H2O+CO2
Moles of CO2=72/24000=0.003
moles of Al4C3= 0.003/3=0.001 (as ratio of Al4C3:CH4 is 1:3)
now mass of Al4C3= 0.001 into (27+27+27+27+12+12+12)=0.144g
____________________________________________________________________________
dis was done by jiyad ahsan
Can somebody explain those?
Righttt i understood the process but how do we know its Al4C3? :/
Righttt i understood the process but how do we know its Al4C3? :/
I did it a bit differently and got the correct answer as well.
72/24000 = 0.003 moles of carbon dioxide.
mass of carbon = 0.003 * 12 = 0.0036g.
0.144 - 0.0036 = 0.108 g of X (Aluminium) left.
0.108/27 = 0.004 of Aluminium
Ratio of Al to C
0.004 : 0.003
4 : 3
therefore it is Al4C3
Somebody please reply fast.. i have 2 hours left. Im done with all the papers back till 2002. Ive gone through my notes once. what should i do right now?? chemguide or the book (coursebook by David Acaster) plz note that I have 2 hours only and went through each looong way back
Hey umm im confused in question number 30 why do we use the moles of the ACID not alcohol? :/ and can anyone pleaase explain me questions number 4, 5 and 12 in the same exam? Thank uQ 30!
okay here goes, so you know when we find the yield in an ester rxn we use the acid right?
so the mass of the ethanoic acid given is 30, which divided by the mr of the acid
30/60 = 0.5 moles
and in the end the ester formed has mass 22g while its mr is 88, moles of ester formed,
22/88 = 0.25 moles
so if 0.5 moles of acid produces o.25 moles of the ester, we have
(0.25/0.5) x 100 = 50%
hope you got it, dnt mind asking if u didnt.
i'll just do 39 and post it up in a bit
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