Physics: Post your doubts here!

[1357911]

why this xtremepapers not opening papers link ???

Some Error I guess. Its the same for everyone. Khudi theek ho jaye ga.

 

[Musab100]

Some Error I guess. Its the same for everyone. Khudi theek ho jaye ga.

Mene paper download karne hain or inn loogoon se site hi band kar di

 

[1357911]

Mene paper download karne hain or inn loogoon se site hi band kar di

freeexampapers.com

 

[1357911]

Mene paper download karne hain or inn loogoon se site hi band kar di

freeexampapers.com

 

[Musab100]

freeexampapers.com

now xtremepapers is working

 

[Musab100]

freeexampapers.com

but thankxx by the way its a good site

 

[adibshamsuddin]

how do we confine oscillations to the plane that are we suppose to observe?

 

[adibshamsuddin]

how do we confine oscillations to the plane that are we suppose to observe? I need the answer for my practical

 

[hassankhan]

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_s05_qp_1.pdf
Can someone explain me q 5,7,11 and 13 of this paper

 

[sellinimmie]

Hello! I'm going to take Paper 3 (AS Practical Skills) this Thursday, and I have a few questions about the exam..
-Are we allowed to bring calculators?
-When are we supposed to repeat readings? Is it when they ask for 6 sets of readings then we're expected to have two readings for one set? For example, when asked for the voltage between a length of a wire, we're going to give two voltage readings for that length, then get their average?

 

[1357911]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s05_qp_1.pdf
Can someone explain me q 5,7,11 and 13 of this paper

Q-5 Where they are asked to find out how long does each pulse rate last... See the graph in the form of a wave pattern. The line is constant between the two waves. So dont take that into account. For the first wave, see how long was the wave at its peak. It is 2 blocks. They have told that 1 block is 1 micrometer second. So 2 blocks will be 2x1 = 2 Micrometer second.

Q-7 The ball is thrown upwards. It is thrown against the force of gravity. So it will be -9.81 ms^-2. It is at the top. Still it is agains the force og gravity. Look at the options now. The only option is B.

 

[1357911]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s05_qp_1.pdf
Can someone explain me q 5,7,11 and 13 of this paper

Q-11. Apply the conservation of Momentum formula.
Initial momentum = Final momentum.
m x 60 - m x 40 (The negative sign represents the object moving in opposite direction) = 2mv (2 because they stick together on impact and also note that both mases are the SAME.)
i.e
m x 60 - m x 40 = 2mv
60m-40m = 2mv
20m = 2mv
m on the left and m on the right cancels out.
so
20/2 = v
v = 10ms^-1

 

[1357911]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s05_qp_1.pdf
Can someone explain me q 5,7,11 and 13 of this paper

Q-13. Upward force = Down ward force.
w1 d1 = w2 d2.
upward force =5 x 2 ( 2 because the whole length is 4. see the rest of the length written as 2m.) (from 5N till 10N)( So 4-2 = 2m )
downward force = 20 x 3 = 60
Look at the clockwise moment now. The one perpendicular to the vertical length 2m.
again w1 d1 10 x 2 = 20
Equate all the three.
5 x 2 = 20 x 3 = 10 x 2
Resultant = (subtract the three) 60 - 20 - 10 = 30

 

[hassankhan]

Q-13. Upward force = Down ward force.
w1 d1 = w2 d2.
upward force =5 x 2 ( 2 because the whole length is 4. see the rest of the length written as 2m.) (from 5N till 10N)( So 4-2 = 2m )
downward force = 20 x 3 = 60
Look at the clockwise moment now. The one perpendicular to the vertical length 2m.
again w1 d1 10 x 2 = 20
Equate all the three.
5 x 2 = 20 x 3 = 10 x 2
Resultant = (subtract the three) 60 - 20 - 10 = 30

Q-13. Upward force = Down ward force.
w1 d1 = w2 d2.
upward force =5 x 2 ( 2 because the whole length is 4. see the rest of the length written as 2m.) (from 5N till 10N)( So 4-2 = 2m )
downward force = 20 x 3 = 60
Look at the clockwise moment now. The one perpendicular to the vertical length 2m.
again w1 d1 10 x 2 = 20
Equate all the three.
5 x 2 = 20 x 3 = 10 x 2
Resultant = (subtract the three) 60 - 20 - 10 = 30

Thank you

Q-13. Upward force = Down ward force.
w1 d1 = w2 d2.
upward force =5 x 2 ( 2 because the whole length is 4. see the rest of the length written as 2m.) (from 5N till 10N)( So 4-2 = 2m )
downward force = 20 x 3 = 60
Look at the clockwise moment now. The one perpendicular to the vertical length 2m.
again w1 d1 10 x 2 = 20
Equate all the three.
5 x 2 = 20 x 3 = 10 x 2
Resultant = (subtract the three) 60 - 20 - 10 = 30

Thank you very much

 

[1357911]

Thank you
Thank you very much

My pleasure.

Anytime.

 

[Musab100]

My pleasure.

Anytime.

can u answer AS chemistry question ??

 

[Musab100]

My pleasure.

Anytime.

can u answer AS chemistry question ??

 

[BAOOZHEN]

HEY everyone please very important for the practical, the last 2 questions always state 4 sources of errors and improvements, please can someone help me with this

 

[hassankhan]

can u answer AS chemistry question ??

which question?

 

[sellinimmie]

Hello! I'm going to take Paper 3 (AS Practical Skills) this Thursday, and I have a few questions about the exam..
-Are we allowed to bring calculators?
-When are we supposed to repeat readings? Is it when they ask for 6 sets of readings then we're expected to have two readings for one set? For example, when asked for the voltage between a length of a wire, we're going to give two voltage readings for that length, then get their average?

ok so calculators are allowed. about the readings, i figured 6 are enough and what needs repeating are the first instructions/questions before that.