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Physics: Post your doubts here!

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Help please QAQ
I think this is the way.Not sure.
p=v^2/r
total r=1/r +1/r+1/r
r=r/3
as is parallel,,,the voltage is same======>p=v^2/r
12=v^2/(r/3)
v^2/r=p
v^2/r=12/3
=4
If the answer is rite,then this wrking should be rite,i guess.
 
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The forces don't pass through a same point so not in equilibrium.
Remember that forces passed through a same point are not necessarily equilibrium, but the forces in equilibrium must pass through a same point ^_^
Thanks a lot buddy,really understand..:)
 
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I think this is the way.Not sure.
p=v^2/r
total r=1/r +1/r+1/r
r=r/3
as is parallel,,,the voltage is same======>p=v^2/r
12=v^2/(r/3)
v^2/r=p
v^2/r=12/3
=4
If the answer is rite,then this wrking should be rite,i guess.

Answer is A :/
 
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Hmmm I think I get it! Just give r a value. Any value of R used the answer will be the same XD!!
Ho ho ho,u r a genius.Btw just want to ask u isnt the p and r resistor become series like i draw above.Thanks ,an A+student prospect is here.
 
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Ho ho ho,u r a genius.Btw just want to ask u isnt the p and r resistor become series like i draw above.Thanks ,an A+student prospect is here.

Erm I think no? Q and R can combine as 1 resistor and become series with p, pls refer to the diagram I draw.
 

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Guys need help here.In this question i get it that the panel 1 and 3 is series together n parallel to 2 ,4.That can be seen by imagining the whole diagram as a circuit.But i dont get it why in option d has a resistor fortm object between points 1 and 3...Thank u.

Guys anyone can help me with this?Thank you a lot.
 

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