Physics: Post your doubts here!

[snowbrood]

Hai ,can anyone help me to solve this doubt?Thanks a lot.Three question from may june 13.

Attached the solution for first question

2nd question pls visit this website： http://www.ocgi.okstate.edu/owpi/EducOutreach/Library/Lesson1_windenergycalc.pdf

3rd question also troubled me. seeking for help too.((

so lets solve 3rd question
simplify the branched resistors
simply the branch (2) the branch at left bottom 1/(1/1+1/1)=0.5ohm
lets simplify the branch (4) right bottom resistors in series are added so 1+1+1=3 ohm
this 3 ohm is parallel to 1 ohm so 1/(1/3+1/1) this simplified (4) to 0.75
all the resistors parralel to 3 volt will get 3 volt right?
so in top row voltage to the point the voltmeter is connnected is (1/2)*3=1.5v
in bottom row voltage to the point the voltmeter is connected is (1.5/2.25)*3=2v
since voltmeter measures the potiential difference it will be 2-1.5=0.5

 

[periyasamy]

so lets solve 3rd question
simplify the branched resistors
simply the branch (2) the branch at left bottom 1/(1/1+1/1)=0.5ohm
lets simplify the branch (4) right bottom resistors in series are added so 1+1+1=3 ohm
this 3 ohm is parallel to 1 ohm so 1/(1/3+1/1) this simplified (4) to 0.75
all the resistors parralel to 3 volt will get 3 volt right?
so in top row voltage to the point the voltmeter is connnected is (1/2)*3=1.5v
in bottom row voltage to the point the voltmeter is connected is (1.5/2.25)*3=2v
since voltmeter measures the potiential difference it will be 2-1.5=0.5
View attachment 32970[/quotE

so lets solve 3rd question
simplify the branched resistors
simply the branch (2) the branch at left bottom 1/(1/1+1/1)=0.5ohm
lets simplify the branch (4) right bottom resistors in series are added so 1+1+1=3 ohm
this 3 ohm is parallel to 1 ohm so 1/(1/3+1/1) this simplified (4) to 0.75
all the resistors parralel to 3 volt will get 3 volt right?
so in top row voltage to the point the voltmeter is connnected is (1/2)*3=1.5v
in bottom row voltage to the point the voltmeter is connected is (1.5/2.25)*3=2v
since voltmeter measures the potiential difference it will be 2-1.5=0.5
View attachment 32970

Thank u a lot.U rock buddy.

 

[Jessie N.]

so lets solve 3rd question
simplify the branched resistors
simply the branch (2) the branch at left bottom 1/(1/1+1/1)=0.5ohm
lets simplify the branch (4) right bottom resistors in series are added so 1+1+1=3 ohm
this 3 ohm is parallel to 1 ohm so 1/(1/3+1/1) this simplified (4) to 0.75
all the resistors parralel to 3 volt will get 3 volt right?
so in top row voltage to the point the voltmeter is connnected is (1/2)*3=1.5v
in bottom row voltage to the point the voltmeter is connected is (1.5/2.25)*3=2v
since voltmeter measures the potiential difference it will be 2-1.5=0.5
View attachment 32970

Awww thank you！！！so the 'All resistances are 1kΩ.' is just distracting. ˊ_>ˋ

 

[snowbrood]

Awww thank you！！！so the 'All resistances are 1kΩ.' is just distracting. ˊ_>ˋ

np just keep praying

 

[princess787]

Hey! Can anyone help me in p1 oct nov 2007! Question 23!! Very complicated!! It's about waves! Thanks ok advance! Really appreciate it!

 

[snowbrood]

Hey! Can anyone help me in p1 oct nov 2007! Question 23!! Very complicated!! It's about waves! Thanks ok advance! Really appreciate it!

23- B
Max speed = 2pi *a *f
f = ?
s = f* lamda
8 = f (50)
0.16 Hz = f

Max speed = 2pi * 2 * 0.16
=2 m/s
Max K.E. = .5 m* v^2 = 0.5 * 2 * 10^-3 * 2^2
= 4 mJ

 

[hope4thebest]

Salam People here is a question related to Current Balance,how do you attempt this?

 

[Muhammad TAimoor]

Question no. 7.
http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_s07_qp_1.pdf

 

[sellinimmie]

Hey!
Is this how the Multiple Choice Answer Sheet looks like:
http://www.cie.org.uk/images/86445-supplementary-multiple-choice-answer-sheet-exam-day-form-2.pdf
..without the E's and numbers > 40??
And are there answers for checking the compiled A level topical Paper 1 questions?
http://www.mediafire.com/?tocg6ha6ihkwd

 

[Ahmad Shujah]

help plzzzzzzzzzzzzzzzzzzzzz

 

[wanderer100]

where can i find examiner report for all paper1...is it possible?
thankyou

 

[periyasamy]

Question no. 7.
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s07_qp_1.pdf

Hope this helps.

 

[periyasamy]

help plzzzzzzzzzzzzzzzzzzzzz

Is it c?Maybe i am wrong.But this is my working.

 

[Muhammad TAimoor]

Hope this helps.

Is this a Right angle Triangle? I thought it wasn't a right angled one, so Pythagoras couldn't be used here..

 

[periyasamy]

Is this a Right angle Triangle? I thought it wasn't a right angled one, so Pythagoras couldn't be used here..

Isnt a vector diagram is definitely with 90 degrees?Try look at the notes i am not sure.

 

[Muhammad TAimoor]

Isnt a vector diagram is definitely with 90 degrees?Try look at the notes i am not sure.

It has to be a Right angled one, but the diagram made it all the more confusing..
Anyway Thanks!

 

[periyasamy]

It has to be a Right angled one, but the diagram made it all the more confusing..
Anyway Thanks!

No problem,buddy.

 

[Mayedah]

http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_s08_qp_4.pdf
uestion 6 part 1 why should it be parallel not normal ?

 

[Dashexdan]

Q9 anyone btw ans D.

 

[Jinosupreme]

Q9 anyone btw ans D.

speed 33 m s^–1
density of the air is 1.2 kg m^–3.
The wall has an area of 12 m^2
What is the force?
First u relate with ur data givien,
So to relate
Density = mass/volume
How u get volume from data?
The only way is to to relate speed and area.
Speed multiply with area
33 X 12 = 396m^3 s^-1

Relate density with this data
1.2 kg m^-3 X 396m^3 s^-1 = 475.2 kg s^-1
Now how to relate to force?
F=ma
F=m(v-u)/t

Since u found m/t = 475.2
Sub ur values
Force = 475.2 (33 - 0)
Force = 15681
= 16000N

 

[Jinosupreme]

Answer is C. Always see this question, but never really understands it.

Anyone explain? Answer B