How were your Physics P-1 and P-3?

[Basaam]

oh alright cheers , i got 24 .. good for me ..

 

[jannat123]

It was easy but question 2 the mass thingy nd finding current was the worst of it

 

[Karim Nabil]

It was easy but question 2 the mass thingy nd finding current was the worst of it

variant 1 ?
if yes, i think finding current was the easiest part there
and for the density question(5 marks), all you've to do is to explain how to obtain mass and volume

 

[Karim Nabil]

The base has nothing to do with answer...But it's Q as the reason I stated


YES!!!One of the hardest questions...I did random stuff and apparantly my friends are saying I did it correct...I did "boiling point OF liquid and Freezing point OF liquid"

no man, idk but they have the same height and the same volume and of the same material
so nothing would be as appropriate as base to be written in account...

 

[jannat123]

No varient 2 I did that
the current part was really tricky
I hope the gt is low

 

[Basaam]

were the currents 0.375 and 1.5 ? variant 1

 

[qassem babel]

its 24 as you would just take the half life

 

[qassem babel]

basaam yes

 

[jannat123]

Can anyone tell the answer of paper 12 the mirror reflection question
its been haunting me plzz

 

[qpKillerqp]

basaam yes

Wait the 2 resistors where 12 and 4...and voltage was 6...so first one in series is "6/16" and second one is "6/(product/sum)which was 3" so answer was 0.375 and 2 right?

 

[qpKillerqp]

the first one was in series , 0.375
the second one was parallel , i got 1.5

hows??the 2 resistors where 12 and 4...product/sum so 48/16=3....6/3=2

 

[qassem babel]

Wait the 2 resistors where 12 and 4...and voltage was 6...so first one in series is "6/16" and second one is "6/(product/sum)which was 3" so answer was 0.375 and 2 right?

Sorry your correct, its 2 it seems I was thinking about something else

 

[Basaam]

hows??the 2 resistors where 12 and 4...product/sum so 48/16=3....6/3=2

tbh i dont really remember its something like that .. i think it was 2 .. but im sure the first one was 0.375

 

[Basaam]

what about the energies in the second or third page .. what did u guys get ?

 

[qpKillerqp]

700,000J and for the 70% efficiency it's something like 1x10^6 or just 1000000

 

[Basaam]

700,000J and for the 70% efficiency it's something like 1x10^6 or just 1000000

the efficiency was already in percentage why did you multiply it by 100 .. ? i might be wrong ..

 

[Mr.Physics]

the efficiency was already in percentage why did you multiply it by 100 .. ? i might be wrong ..

I got the same

 

[qpKillerqp]

simple equation of (output/input)x100=70

 

[Basaam]

I got the same

did you get 10000 ? 1x10^4 ?

 

[Mr.Physics]

No lets see
U have have output as 700,000 J
NOW THE EFFICIENCY IS 70 %
efficiency=output power/input power


70% is 70/100

70/100=700,000/input power

So input power =100/70 x700,000 =1,000,000 J

NOW IF U CONSIDER THEM !
700,000/1,000,000 = 70/100 =70 %

Simple