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Physics: Post your doubts here!

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Which formula could be correct for the speed v of the ocean waves in terms of the density p of sea water, the acceleration of free fall g, the depth of the ocean h and the wavelength, lambda?
 
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Q.9
Impulse (or change in momentum) = Force * time
Impulse = 60 * 0.5 = 30 Ns

Initial momentum of trolley = 30 kg * 3 m/s= 90 Ns
Impule (or change in mometum) = 30 Ns
So final momentum = 90 - 30 = 60 Ns
Final speed = final momentum/mass

Aww thanks. totally forgot to find the speed!! :) Thank you so so much!!
 
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Sorry Hadi, but can you please explain a bit more about this? :)
yes ofcourse. dat wuz a crappy explanation anyway.

Vx = V*cos(45) = V * (1/√2) = V/√2
Vy = V*sin(45) = V * (1/√2) = V/√2

E = (1/2) * m * (v)²
E = Ex + Ey

Ex = (1/2) * m * (V/√2)²
Ex = m/2 * V²/2
Ex = mV²/4

Ey = (1/2) * m * (V/√2)²
Ey = m/2 * V²/2
Ey = mV²/4

Initial E = Ex + Ey = (mV²/4) + (mV²/4)
Initial E = mV²/2

^^This is da moment when da object is launched in da air.

At maximum height, vertical velocity becomes 0 which means Vy = 0 , so Ey also becomes 0
Hence
Final E = Ex only
Final E = mV²/4

Now compare Final E wid Initial E.
Final E is 1/2 of Initial E
So answer is 0.5E
 
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