Maths, Addmaths and Statistics: Post your doubts here!

[exploded diper]

Q3.b

did u get it?

 

[FLRNAB]

lg to sahi raha hai

Thanks

Yes it is though i think one of the bars is slightly higher or lower,and thats a mistake..Though its a really impossible speed time graph.How can he be traveling at 17 and stop at the same moment,his inertia would literally cause his bones to move out of his body if he stopped faster than the speed of light

The graph is accurate to 1 sec only.

He went from 1,017 km/h to a dead stop in 1.4 seconds. John Shtapp

but i dont think there should be the vertical line after 13 40

The question graph shows he has no speed between that time frame.

 

[exploded diper]

its X=-1 since its 2 spaces away from triangle A and 4 spaces away from C since its a shear by x2

the question says its a stretch......

 

[asadalam]

Thanks

The graph is accurate to 1 sec only.

He went from 1,017 km/h to a dead stop in 1.4 seconds. John Shtapp


The question graph shows he has no speed between that time frame.

But still its a pretty fast stop

 

[exploded diper]

Thanks

The graph is accurate to 1 sec only.

He went from 1,017 km/h to a dead stop in 1.4 seconds. John Shtapp


The question graph shows he has no speed between that time frame.

y change the pic....

 

[funky brat]

http://papers.xtremepapers.com/CIE/...Calculator Version) (4024)/4024_s12_qp_22.pdf
Question 9 c part 3 b anyone?

 

[exploded diper]

MORE PARTS COMING RUGHT UP.....

 

[exploded diper]

 

[exploded diper]

so thts it...

 

[Mahnoorfatima]

http://papers.xtremepapers.com/CIE/...(Calculator Version) (4024)/4024_w06_qp_1.pdf
Question 8 part c. How do we solve such questions??

 

[asadalam]

http://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w06_qp_1.pdf
Question 8 part c. How do we solve such questions??

Factors are 2^3 3^2 and 5 so if we have to find the number to multiply to get perfect cube we will make the factors all cubed e.g 2^3 3^3 and 5^3

Notice i have multiplied one more 3 and 2 fives to obtain a perfect cube,That is the smallest integer we need to multiply with i.e 3 x 5^2 = 75 so k will be 75

 

[Mahnoorfatima]

Factors are 2^3 3^2 and 5 so if we have to find the number to multiply to get perfect cube we will make the factors all cubed e.g 2^3 3^3 and 5^3

Notice i have multiplied one more 3 and 2 fives to obtain a perfect cube,That is the smallest integer we need to multiply with i.e 3 x 5^2 = 75 so k will be 75

Right. One more thing. If there was perfect square instead of cube, we'd do the same process?

 

[asadalam]

Right. One more thing. If there was perfect square instead of cube, we'd do the same process?

Similar but not the same.We would make the factors all square like multiply by 5 and divide by 2 to get all factors squared.The multiplying integer would give us a perfect square then.

 

[kirann]

would somebody explain me part a mein kya krna hai?

 

[DaniyalK]

would somebody explain me part a mein kya krna hai?View attachment 43731

When y = 0, x^3 = 5. So you just have to write down the value of x when y = 0. From the graph, it's 1.7.

 

[exploded diper]

whats the difference between sub set and proper subset

 

[exploded diper]

would somebody explain me part a mein kya krna hai?View attachment 43731

is this paper 1.........

 

[kirann]

is this paper 1.........

yes nov 2008

 

[Mahnoorfatima]

Similar but not the same.We would make the factors all square like multiply by 5 and divide by 2 to get all factors squared.The multiplying integer would give us a perfect square then.

Wait.. what? Why are we dividing by two? I know I'm bothering you but .. I need to understand it.

 

[asadalam]

whats the difference between sub set and proper subset

A set is a collection of elements. For instance, {1, 2, 3} is a set containing 3 elements (namely, the elements "1", "2", and "3").

Set X is a subset of set Y if and only if every element in X is also an element of Y.

Set X is a proper subset of set Y if and only if X is a subset of Y and X != Y.


So for instance, {1, 2, 3} is a subset (but not a proper subset) of {1, 2, 3}.
{1, 2} is a proper subset of {1, 2, 3}.