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did u get it?Q3.b
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did u get it?Q3.b
Thankslg to sahi raha hai
The graph is accurate to 1 sec only.Yes it is though i think one of the bars is slightly higher or lower,and thats a mistake..Though its a really impossible speed time graph.How can he be traveling at 17 and stop at the same moment,his inertia would literally cause his bones to move out of his body if he stopped faster than the speed of light
The question graph shows he has no speed between that time frame.but i dont think there should be the vertical line after 13 40
the question says its a stretch......its X=-1 since its 2 spaces away from triangle A and 4 spaces away from C since its a shear by x2
But still its a pretty fast stopThanks
The graph is accurate to 1 sec only.
He went from 1,017 km/h to a dead stop in 1.4 seconds. John Shtapp
The question graph shows he has no speed between that time frame.
y change the pic....Thanks
The graph is accurate to 1 sec only.
He went from 1,017 km/h to a dead stop in 1.4 seconds. John Shtapp
The question graph shows he has no speed between that time frame.
Factors are 2^3 3^2 and 5 so if we have to find the number to multiply to get perfect cube we will make the factors all cubed e.g 2^3 3^3 and 5^3http://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w06_qp_1.pdf
Question 8 part c. How do we solve such questions??
Right. One more thing. If there was perfect square instead of cube, we'd do the same process?Factors are 2^3 3^2 and 5 so if we have to find the number to multiply to get perfect cube we will make the factors all cubed e.g 2^3 3^3 and 5^3
Notice i have multiplied one more 3 and 2 fives to obtain a perfect cube,That is the smallest integer we need to multiply with i.e 3 x 5^2 = 75 so k will be 75
Similar but not the same.We would make the factors all square like multiply by 5 and divide by 2 to get all factors squared.The multiplying integer would give us a perfect square then.Right. One more thing. If there was perfect square instead of cube, we'd do the same process?
When y = 0, x^3 = 5. So you just have to write down the value of x when y = 0. From the graph, it's 1.7.would somebody explain me part a mein kya krna hai?View attachment 43731
is this paper 1.........would somebody explain me part a mein kya krna hai?View attachment 43731
yes nov 2008is this paper 1.........
Wait.. what? Why are we dividing by two? I know I'm bothering you but .. I need to understand it.Similar but not the same.We would make the factors all square like multiply by 5 and divide by 2 to get all factors squared.The multiplying integer would give us a perfect square then.
A set is a collection of elements. For instance, {1, 2, 3} is a set containing 3 elements (namely, the elements "1", "2", and "3").whats the difference between sub set and proper subset
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