-
We need your support!
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
Physics: Post your doubts here!
- Thread starter XPFMember
- Start date
- Messages
- 129
- Reaction score
- 203
- Points
- 53
You should have read the post many time to understand:
Always remember "Intensity is directly proportional to amplitude square" , Revise the waves chapter,
Intensity proportional to (Amplitude) ^2
So, if the wave has an amplitude of A
The intensity will be proportional to (A)^2
If it has amplitude of 2A
The intensity will be proportional to (2A)^2 = 4A^2
If it has amplitude of 10
The intensity will be proportional to (10)^2 = 100
If it has amplitude of 20
The intensity will be proportional to (20)^2 = 400
I hope you have got it
, If not yet i want you to revise the chapter,Sorry for late reply i have extremely unstable network and having problems in my area!
You should have read the post many time to understand:
Always remember "Intensity is directly proportional to amplitude square" , Revise the waves chapter,
Intensity proportional to (Amplitude) ^2
So, if the wave has an amplitude of A
The intensity will be proportional to (A)^2
If it has amplitude of 2A
The intensity will be proportional to (2A)^2 = 4A^2
If it has amplitude of 10
The intensity will be proportional to (10)^2 = 100
If it has amplitude of 20
The intensity will be proportional to (20)^2 = 400
I hope you have got it
Sorry for late reply i have extremely unstable network and having problems in my area!
yup got this THANKS aLOT
the thing i didn't get is how we changed
I=power/area to I=A^2/S
Sorry for bothering you again
- Messages
- 8,477
- Reaction score
- 34,837
- Points
- 698
First find p.d between S and P then between S and Q
Formula we'll take in account is :
Resistance across p.d / Total resistance * voltage
Case i) - b/w S and P :¬
5000 / 10000 * 2 = 1V1
case ii) - b/w S and Q :¬
3000 / 5000 * 2 = 1.2V2
Now we are asked to find V1 - V2
Hence 1 - 1.2 = -0.2V = C
- Messages
- 8,477
- Reaction score
- 34,837
- Points
- 698
26)
I ¹/α x² so, doubling x means I would be divided by 4.
I α A² so, √(8²/4) = √16 = 4.0 μm
This can also be done like this :¬
I1/ I2 = A1² / A2²
1/(1/4) = 8² /x²
4/8² = 1/x²
x²= 16
x= √16
x= 4.0 μm
- Messages
- 8,477
- Reaction score
- 34,837
- Points
- 698
What is the question ?
- Messages
- 8,477
- Reaction score
- 34,837
- Points
- 698
24)
intensity 1/α area and α amplitude squared
dividing area by 3 cause the power per unit area (i.e intensity) to increase by a factor of 3 and, increasing the amplitude by 2 causes the intensity to increase by a factor of 4
--> therefore (4x4)P=12P
- Messages
- 8,477
- Reaction score
- 34,837
- Points
- 698
P = ρgh + Atmospheric P
P = 1000*10*5 + 100000 = 150000 = C
- Messages
- 324
- Reaction score
- 537
- Points
- 103
- Messages
- 29
- Reaction score
- 91
- Points
- 13
how did physics paper 12 go? i found it really hard :/
- Messages
- 8,477
- Reaction score
- 34,837
- Points
- 698
https://www.xtremepapers.com/commun...sion-for-physics-and-chemistry-paper-1.33891/do u know where i can physics formulas
Pls hurry
- Messages
- 8,477
- Reaction score
- 34,837
- Points
- 698
i'll get around 35 mene 5 tuke lagaye . _ .
- Messages
- 324
- Reaction score
- 537
- Points
- 103
- Messages
- 29
- Reaction score
- 91
- Points
- 13
I wonder what the grade threshold will be for it