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somebody please explain why do we have to multiply moles of H2 by 2? I have my mock tomorrow
Send me a proper pic.. I need the data
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somebody please explain why do we have to multiply moles of H2 by 2? I have my mock tomorrow
In A it's propane and the reactions will continue till conditions are maintained so you may get 1-chloropropane or 2-chloropropane.(Keep this in mind if we have no other better options we will go with this)View attachment 51450
How come its C ?? ( I choose A)
yes. I didn't get why u multiplied the moles of H2 by 2?
Initially, they are adding 1 mol each of H2O and CO, yea? And the initial no. of moles of products is 0. That is a total of 2 moles.
You must know that, whatever the position of equilibrium, the total no. of moles will remain constant; in this case 2.
Now, given that, at equilibrium, 33.3% of the total moles (2) is H2 (we can take volume as moles as all are gases) ...
n(H2) = 33/100 * 2 = 0.666
Then comes the rest of the calculations.
Do be very careful of the assumption that the total moles would remain constant, conceptually, it is wrong.
It works in this unique question as the sum of the stoichiometric coefficients are the same on both sides.
Using an example, pretending that Nitrogen and Hydrogen reacts irreversibly to form ammonia
N2 + 3H2 --> 2NH3
Using 1 mole of N2 and 3 moles of H2 will not give us (1+3) moles of NH3.
http://onlineexamhelp.com/wp-content/uploads/2013/10/9701_s13_qp_22.pdf
Question 5 part d)i) how is it ethanoic acid?
http://onlineexamhelp.com/wp-content/uploads/2013/10/9701_s12_qp_22.pdf
Question3
HO2CCH2CH(OH)CO2H <--That’s the acid given
and then in part B the reaction is heat with CH3CO2H/H+ <--This to is an acid...
so the Mark scheme says HO2CCH2CH(OH)CO2H (with CH3CO2H/H+)-->View attachment 51470
How did that form?
NAHCO thngy teacts only wth ethanoic acid (its an acid base reacn) to give CO2http://onlineexamhelp.com/wp-content/uploads/2013/10/9701_s13_qp_22.pdf
Question 5 part d)i) how is it ethanoic acid?
http://onlineexamhelp.com/wp-content/uploads/2013/10/9701_s12_qp_22.pdf
Question3
HO2CCH2CH(OH)CO2H <--That’s the acid given
and then in part B the reaction is heat with CH3CO2H/H+ <--This to is an acid...
so the Mark scheme says HO2CCH2CH(OH)CO2H (with CH3CO2H/H+)-->View attachment 51470
How did that form?
For the first one you need to have a glance at your structures and think what will be left when each ester is hydrolyzed.For eg when i drew the isomers I got my answer as W.The formula for W was CH3CO2CH2CH3 now in this case you are getting CH3CO2H as your acid and instead of an Alchol I am getting an Alkane CH3CH3. There you go it's not an aldehyde nor a ketone.http://onlineexamhelp.com/wp-content/uploads/2013/10/9701_s13_qp_22.pdf
Question 5 part d)i) how is it ethanoic acid?
http://onlineexamhelp.com/wp-content/uploads/2013/10/9701_s12_qp_22.pdf
Question3
HO2CCH2CH(OH)CO2H <--That’s the acid given
and then in part B the reaction is heat with CH3CO2H/H+ <--This to is an acid...
so the Mark scheme says HO2CCH2CH(OH)CO2H (with CH3CO2H/H+)-->View attachment 51470
How did that form?
I know its an ACID but why ethanoic was my question.NAHCO thngy teacts only wth ethanoic acid (its an acid base reacn) to give CO2
It neither reacts wth a carbonyl comp nor wth ethanol so its an acid
I didnt get youFor the first one you need to have a glance at your structures and think what will be left when each ester is hydrolyzed.For eg when i drew the isomers I got my answer as W.The formula for W was CH3CO2CH2CH3 now in this case you are getting CH3CO2H as your acid and instead of an Alchol I am getting an Alkane CH3CH3. There you go it's not an aldehyde nor a ketone.
Which is more acidic, 2-chloropropanoic acid or 3-chloropropanoic acid? Explain your answer.
I think 2-chloropropanoic acid because it will have more electron withdrawing effect. Am I correct?
I know its an ACID but why ethanoic was my question.
Thnx
molecular formula= C4H8O2Did you find out what is the formula of Q?
That is the ester right?molecular formula= C4H8O2
What if THIS equation had 2 moles on one side and 3 on other..?
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