Chemistry: Post your doubts here!

[princess Anu]

moreover, we just have to look if the total moles at one side are equal to moles on the other side for this method? We donot have to consider the individual moles of compounds right? And this methold is true for all the reactions or only reversible?

 

[princess Anu]

in an ionic equation we do write acids such as HNO3 in their ionic forms right?
Q what can be the two structural isomers for penton-3-one?

 

[ashcull14]

 

[Metanoia]

What if THIS equation had 2 moles on one side and 3 on other..?
We couldnot solve it right?

If we use the equilibrium table, it doesn't matter if the moles are different on both sides. We just adjust the values in the table accordingly.

I'll create a imaginary reaction just for example, keeping the % as 33.3% .

 

[Metanoia]

View attachment 51474

Sodium chloride solution is neutral.
The other 3 chlorides are acidic.

 

[ashcull14]

Q what can be the two structural isomers for penton-3-one?[/QUOTE]

one more could be if u place the CO group on second carbon atom rather than 3rd

 

[Metanoia]

moreover, we just have to look if the total moles at one side are equal to moles on the other side for this method? We donot have to consider the individual moles of compounds right? And this methold is true for all the reactions or only reversible?

I would really advised against checking the sum of moles of reactants vs products.

Use the Initial/Change/Equilibrium table, that works for all cases.

 

[ashcull14]

Sodium chloride solution is neutral.
The other 3 chlorides are acidic.

but isn't sodium chloride gona react with water to form an alkaline sol ?

 

[Metanoia]

in an ionic equation we do write acids such as HNO3 in their ionic forms right?
Q what can be the two structural isomers for penton-3-one?

This sounds a bit strange, penton-3-one has only one structure.

 

[Metanoia]

but isn't sodium chloride gona react with water to form an alkaline sol ?

Nope. NaCl is a neutral solution,

But to explore your thoughts of it forming an alkaline solution, could you try to write an equation to that?

 

[ashcull14]

Could you try to write an equation to that?

NaCl + H2O = NaOH + HCl

 

[Metanoia]

NaCl + H2O = NaOH + HCl

You realized that you have actually formed an acid also? HCl.

The reverse reaction is actually what would happen if there is NaOH and HCl.

Its the neutralization reaction between HCl and NaOH.

 

[princess Anu]

View attachment 51465 can somebody do Q 4

 

[ashcull14]

You realized that you have actually formed an acid also? HCl.

The reverse reaction is actually what would happen if there is NaOH and HCl.

Its the neutralization reaction between HCl and NaOH.

thnks ...........

 

[princess Anu]

You realized that you have actually formed an acid also? HCl.

The reverse reaction is actually what would happen if there is NaOH and HCl.

Its the neutralization reaction between HCl and NaOH.

You mean this does happen?

 

[ashcull14]

your que has a misprint .......how many times the vol M? think it has been solved bfor

 

[Metanoia]

View attachment 51477Q what can be the two structural isomers for penton-3-one?

one more could be if u place the CO group on second carbon atom rather than 3rd[/QUOTE]

My concern is that these are actually "isomers of pentanone", not "isomers of penton-3-one".

There is only one structure that penton-3-one, CH3CH2COCH2CH3.

So the question wording is a bit strange.

 

[princess Anu]

View attachment 51477Q what can be the two structural isomers for penton-3-one?

This question actually came in my paper..
the first one was already drawn and we had to make two others.
I made the second one ,you have drawn, but i am doubtful because this changes the position of functional group from 1 to 2.. what should be the answer

This sounds a bit strange, penton-3-one has only one structure.

 

[The Chill Master]

I know its an ACID but why ethanoic was my question.
Thnx anyway

I didnt get you

Ya the way Metanoia explained is right.
I was doing it wrong.

 

[The Chill Master]

That is the ester right?

Then the question states that Q is hydrolyzed with sulfuric acid

C4H8O2 --> acid + alcohol

Then the mixture was oxidized to obtained a single product, R, in other words, the alcohol in the above reaction is oxidized to become the same compound as the acid.

It simply means the alcohol has the same number of carbons as the acid.

We have 4 carbons to divide equally among the two....so the alcohol was ethanol and the acid was ethanoic acid.

When this mixture was oxidized, all we end up with is a sample of ethanoic acid.

Thanks a lot