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https://docs.google.com/viewerng/vi.../wp-content/uploads/2012/11/9701_s08_qp_1.pdf
Can someone show me the calculation for qs 6 ?
thank u
Can someone show me the calculation for qs 6 ?
thank u
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m = 1ghttps://docs.google.com/viewerng/vi.../wp-content/uploads/2012/11/9701_s08_qp_1.pdf
Can someone show me the calculation for qs 6 ?
thank u
wow im so dumb .-. i was doing such a long method :/m = 1g
mr = 18
n = 1/18
V = nRT/P
V = 1/18 * 8.32 * 596 / 101000 = 2.72dm^3 (the answer difference is due to change in dp)
Should be C, 2 and 3.Could someone please answer 2011 May/June Paper 12 Question 35. The mark scheme says the answer is A but the same question is in 2008 May/June(Question 36) and the answer there is C.
Thanks.
This is due to electronegativity of N > P. Detail explained here:¬shoudn't it be 107? then how is it B?:sView attachment 54675
You mean I should chose 104 instead 107? if 107 was given as an option ? :OThis is due to electronegativity of N > P. Detail explained here:¬
http://www.meritnation.com/ask-answ...mical-bonding-and-molecular-structure/1061393
Basically, answer is not 104 as well... Its just less then 109 degrees... so option here is give 104 so that is correct... if it was 107 given and 104 you should know 104 is the correct choice.. 90 and 104.. 90 is the correct and nearest degree..
Dear, Image too small that i cant see even when i zoom it, its appearing blurred.
Sorry, no time : https://www.xtremepapers.com/commun...st-your-doubts-here.9859/page-381#post-745892The Sarcastic Retard qwertypoiu I need help in this question ...
Here i have posted the link for the question paper and my doubt is in question no 21 ....
I have even posted the explanation for Q21 which was answered previously .... My doubt is I don't get what they are trying to say in the part where i have highlighted ... so can one of you clarify it to me further.. Thanks in advance
https://docs.google.com/viewer?a=v&...sLm9yZ3x0ZWFjaGVyc3xneDoxYmI0OTYwOWIyZDRmNWVj
If the compound was an alkane and had no rings or double bonds, number of H atoms present = 2n+2 = 2(20)+2 = 42
Now, every time there're 2H less, you'll either have a double bond or a ring. The question states that there's one aldehyde (C=O) and 1 ring structure which has 1 C=C so this accounts for 6 missing Hydrogens, thereby leaving you with 8 missing Hydrogens.
8/2 = 4 Hydrogens in the aliphatic side chain.
However, total C=C are 5 because you have to include the C=C from the cyclohexene + cis formation hence A
Its alright .. he has actually replied to the wrong question
34 ans is C ?Can someone please explain these:
MJ 14/11 Q8, 13, 34. Thank you.
Please explain them. Thanks.34 ans is C ?
34 is B bro...34 ans is C ?
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