• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Chemistry: Post your doubts here!

Messages
924
Reaction score
1,096
Points
153
The Sarcastic Retard qwertypoiu I need help in this question ...

Here i have posted the link for the question paper and my doubt is in question no 21 ....
I have even posted the explanation for Q21 which was answered previously .... My doubt is I don't get what they are trying to say in the part where i have highlighted ... so can one of you clarify it to me further.. Thanks in advance

https://docs.google.com/viewer?a=v&...sLm9yZ3x0ZWFjaGVyc3xneDoxYmI0OTYwOWIyZDRmNWVj

If the compound was an alkane and had no rings or double bonds, number of H atoms present = 2n+2 = 2(20)+2 = 42

Now, every time there're 2H less, you'll either have a double bond or a ring. The question states that there's one aldehyde (C=O) and 1 ring structure which has 1 C=C so this accounts for 6 missing Hydrogens, thereby leaving you with 8 missing Hydrogens.

8/2 = 4 Hydrogens in the aliphatic side chain.

However, total C=C are 5 because you have to include the C=C from the cyclohexene + cis formation hence A
I will assume you have understood the parts you did not highlight. So there would have been 42 hydrogen atoms, if it were just a straight chain alkane. We wish for only 28 to be left.
6 hydrogen atoms are accounted for by the presence of aldehyde and ring structure. So 42-6 = 36 we'd expect now.
However we wish for 28. We need to eliminate 36-28= 8 more hydrogen atoms.
Every time a double bond is added to a saturated chain, 2 hydrogen atoms are gotten rid of.
Therefore, 8/2 = 4 double bonds required to satisfy our condition.
 
Messages
26
Reaction score
16
Points
3
Aluminium carbide, Al 4C3, reacts readily with aqueous sodium hydroxide. The two products of the

reaction are NaAlO2 and a hydrocarbon. Water molecules are also involved as reactants.

What is the formula of the hydrocarbon?

A CH4
B C2H6
C C3H8
D C6H12
someone explain this plz the answer is A

Reaction => Al4C3 + 4NaOH + 4H2O --> 4NaAlO2 + 3CH4. You'll end up at this if you try to balance the equation.
 
Messages
18
Reaction score
3
Points
3
Use of the Data Booklet is relevant to this question.

A sample of potassium oxide, K2O, is dissolved in 250cm3 of distilled water. 25.0cm3

solution is titrated against sulfuric acid of concentration 2.00moldm–3. 15.0 cm3 of this

acid is needed for complete neutralisation. of this sulfuric

Which mass of potassium oxide was originally dissolved in 250cm3 of distilled water?

A 2.83g
B 28.3g
C 47.1g
D 56.6g
 
Messages
924
Reaction score
1,096
Points
153
Use of the Data Booklet is relevant to this question.

A sample of potassium oxide, K2O, is dissolved in 250cm3 of distilled water. 25.0cm3

solution is titrated against sulfuric acid of concentration 2.00moldm–3. 15.0 cm3 of this

acid is needed for complete neutralisation. of this sulfuric

Which mass of potassium oxide was originally dissolved in 250cm3 of distilled water?

A 2.83g
B 28.3g
C 47.1g
D 56.6g
K2O + H2SO4 ----> K2SO4 + H2O
Moles of acid = 15/1000*2 = 0.03mol
Moles of K2O in 25cm3 = 0.03mol, due to ratio.
Moles of K2O in 250cm3, = 0.03*10 = 0.3mol
Mass = (39.1*2+16)*0.3 = 28.26g
 
Messages
18
Reaction score
3
Points
3
K2O + H2SO4 ----> K2SO4 + H2O
Moles of acid = 15/1000*2 = 0.03mol
Moles of K2O in 25cm3 = 0.03mol, due to ratio.
Moles of K2O in 250cm3, = 0.03*10 = 0.3mol
Mass = (39.1*2+16)*0.3 = 28.26g
oh i didnt multiply it by 10 he wanted it in the distilled solution.thx mate what r u studing?a levels or as
 
Messages
3,770
Reaction score
34,813
Points
523
I will assume you have understood the parts you did not highlight. So there would have been 42 hydrogen atoms, if it were just a straight chain alkane. We wish for only 28 to be left.
6 hydrogen atoms are accounted for by the presence of aldehyde and ring structure. So 42-6 = 36 we'd expect now.
However we wish for 28. We need to eliminate 36-28= 8 more hydrogen atoms.
Every time a double bond is added to a saturated chain, 2 hydrogen atoms are gotten rid of.
Therefore, 8/2 = 4 double bonds required to satisfy our condition.
Thanks alot :D JazakAllah khairan :D
 
Messages
72
Reaction score
35
Points
18
View attachment 54717 how do we read the benzene rings? why is C chiral and not D?
benz1.gif

Every Carbon in Benzene ring has a double bond so none of the carbons in a benzene ring are chiral. C is chiral because Central C atom is Connected to the following groups:
1) OH
2) CH3
3) Benzene Ring
4) OH Benzene Ring

4 different groups so it is chiral. Central Atom C in part D is connected to:
1) OH
2) CO2CH2CH3
3) OH Benzene Ring
4) OH Benzene Ring
 
Messages
1,229
Reaction score
740
Points
123
hey you missed out the OH group attached to the benzene ring in option C (it wasn't printed properly :p )Screen Shot 2015-06-07 at 12.16.29 PM.png .. look at the question again
 
Top