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Thanks dear for your answer, but I was specifically needing help for no. 2, I don't know how to make [Pb2+] equal to [Cl-]. I hope you understand when the power is 1 for the concentration I can calculate it easily but I am having problem when there is a power greater than 1...........waiting for your response
Let concentration of eqm concentration of Pb2+ be x
[Cl-] = 2x
Ksp = [Pb2+][Cl-]^2
= (x) (2x)^2
= (x)(4x^2)
= 4x^3