- Messages
- 1,394
- Reaction score
- 12,123
- Points
- 523
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
I guess.So they will be in data booklet
Great ^_^
N abt the ionic radius
Its the distance b/w the nuclues and the outershell if the ion
Am i ryt?
OkI guess.
You should know what energies to use in the born-haber cycle. And to find lattice energy,Ok
N how do we find if we have to add up all energies given in Born haber cycle or subtract them to find lattice energy ?
HmmYou should know what energies to use in the born-haber cycle. And to find lattice energy,
Latt energy change = Enthalpy change of formation - (the sum of rest of the energies you use in the cycle)
You will understand better if you try a past paper question on this.
Thanks buddy tho i do edexcel not ciezahra azam ... you could try 42/m/j/14 - Q2d
Is edexcel easier than cie?Thanks buddy tho i do edexcel not cie
I will say both stand on the same levelIs edexcel easier than cie?
Nope ... don't get yourself confused like that with a particular formula. If you draw the Born-Haber cycle (I hope you know how to?) you will see what needs to be added and subtracted with the arrows ... and this cycle is just a more advanced version of Hess'law so you can can just take the different routes and well, you know, calculate whatever energy you want.Hmm
Is it not like lattice energy and the electron affinity= rest of energies on the left side?
If you can, find a question in edexcel and do ... or it wouldn't hurt to do this as well ... just practice so you can understandThanks buddy tho i do edexcel not cie
Yep thankfully i do know how to draw it xDNope ... don't get yourself confused like that with a particular formula. If you draw the Born-Haber cycle (I hope you know how to?) you will see what needs to be added and subtracted with the arrows ... and this cycle is just a more advanced version of Hess'law so you can can just take the different routes and well, you know, calculate whatever energy you want.
If you can, find a question in edexcel and do ... or it wouldn't hurt to do this as well ... just practice so you can understand
coolYep thankfully i do know how to draw it xD
Yep i did one of the qs in my book ur way
It works
Thanks
Yeah..I also got the same, then I thought they must have made it a ratio but then that's also no rule! so I was so confused, thought I wasn't calculating the oxidation states right, went back to the book, read again and again, read on the web, on chemguide then listened khanacademy...everything actually! but still....so this is it the question was wrong...I just found these topicals on the web but seems like they aren't authentic enough and questions can be wrong!are they taking the ratio of the changes or sth? Coz Chlorine's oxdn state is decreasing by 2 and Sulphur's by 4 ...
so its B?
Yeah...this is it! Thanks a lot!
Yes, some topics in that book do contain question which relate to A2. However it is good for practice. Do this book for practice only, but focus more on the yearly ones.Yeah..I also got the same, then I thought they must have made it a ratio but then that's also no rule! so I was so confused, thought I wasn't calculating the oxidation states right, went back to the book, read again and again, read on the web, on chemguide then listened khanacademy...everything actually! but still....so this is it the question was wrong...I just found these topicals on the web but seems like they aren't authentic enough and questions can be wrong!
Yeah...this is it! Thanks a lot!
I have a topical MCQs book for chemistry, "1000 chemistry MCQs with Help", but I found that questions set there contain syllabus from A2, which must be part of AS in old syllabus...any idea?
8a) (iii) By cross linking polymer chains it means, the link between the polymer chains which would be the same chains up and down............ so the cross link between them: HOCH2(CH2OH)C(CH2OH) CH2OH (thus the power 4 in the ms). The H at the top and bottom come because we r talking about it individually, when combined, the COO gets attached instead.http://maxpapers.com/wp-content/uploads/2012/11/9701_s13_qp_42.pdf
q:8a (iii)..why is that structure?
8c(i): how come there's no reduction in OH?
Which paper ?Use hess's law to calculate the standard enthalpy change of hydration of MgSO4
I know the method but answer is not correct
Can anyone explain it to me? :3
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now