- Messages
- 456
- Reaction score
- 280
- Points
- 73
Damn mashallah! ThanksP(1.9 - b < X < 1.9 + b) = 0.80
P(X < 1.9 + b) - P(X < 1.9 - b) = 0.80
Standardizing X, using Z = X - μ / σ
P( Z < 1.9 + b - 1.9 / 0.15 ) - P(Z < 1.9 - b -1.9) = 0.80
P(Z< b/0.15) - P(Z <-b/0.15) = 0.80
Ф(b/0.15) - Ф(-b/0.15) = 0.80
2Ф (b/0.15) - 1 = 0.80
2Ф (b/0.15) = 1.80
Ф (b/0.15) = 0.90
Using Normal Distribution tables,
b/0.15 = 1.281
b = 0.192 (3sf)
You can now use this value of b to find the safety limits.