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In part (i) it says that there must be ATLEAST 2 trees of each type. Concentrate on the word ATLEAST. It means that this is the minimum requirement of each tree and there can more than two trees of each type.In the first part why isn't 4C2*9C2*2C2 the right way to get to the answer since we have to choose from 4 9 and 2 types of tress?
And part iiii as well please explain.
The available quantity of trees is : 4 Hibiscus tree, 9 Jacaranda trees, and 2 oleandars.
Now the possible selections in which there are atleast 2 trees of each type are:
2 hibiscus, 8 jacaranda, and 2 oleandars <---- the ways for doing this are : 4C2 * 9C8 * 2C2
3 hibiscus, 7 jacaranda, and 2 oleanders <---- the ways for doing this are : 4C3 * 9C7 * 2C2
4 hibiscus, 6 jacaranda, and 2 oleanders <---- the ways for doing this are : 4C4 * 9C6 * 2C2
Now sum the above, to find the total no. of ways, which are : 54 + 144 + 84 = 282 ways.
In part (iii), it says that there should be any Hibiscus trees together.
Let the hibiscus trees be represented by ' * 's
and the other two types to be represented by ' X 's.
Now the possible positions for the trees that no hibiscus trees are together are :
* X * X * X * X * X * X * X * X *
Now arrange the trees in these positions.
The no. of arrangements of the 9 trees (jacaranda and oleander) in places marked by X are : 8!
There are 4 hibiscus trees, so select 4 positions marked by * from the shown 9 positions. This will be done in 9C4 ways.
Now the positions have been selected, so arrange the 4 hibiscus trees in these 4 selected positions: 4!
Now combine all this stuff to find the total no. of possible arrangements: 8! * 9C4 * 4! = 121927680 arrangenments.