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We are given:Can anyone help me with this question?
In a spot check of the speeds x km/hr of 30 cars on a motorway, the data were summarised by Σ(x-110) = -47.2 and Σ(x-110)^2 = 5460. Calculate the mean and standard deviation of these speeds.
Σ(x-110) = -47
Σ(x-110)^2 = 5460
n=30
let y= x-110
Σy=-47.2 and Σy^2=5460
ȳ=-47.2/30 =-1.57
since y=x-1110
ȳ= x̅-110
x̅=ȳ+110
=-1.57 +110
=108.43
For SD calculate the sd of y
√Σy^2 /n -(ȳ)^2 (you know the normal formula we use to find the standard deviation, I can't seem to type it correctly)
√(5460/30)-(-1.57)^2
=13.4
SD of x =SD of y
so SD of x is 13.4 as well