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Yes that would be wrong. The other carbon atom is neutral because it is bonded to four atoms.View attachment 59769
If i put the positive charge on the other double bonded carbon atom, is it wrong ?
0.1 moldm-3 solution of Fe2(SO4)3 (aq)
I think you misunderstood.Yes that would be wrong. The other carbon atom is neutral because it is bonded to four atoms.
Oh I see. Well I'm not sure but I think order of bonding (which carbon bromine bonds to first) should not matter.I think you misunderstood.
I meant that in the mark scheme they put the + sign on the carbon atom with one hydrogen atom. So the Br bonded to the carbon atom with two hydrogen atoms first.
My question is if i put the +sign on the carbon atom with two hydrogen atoms and bonded the Br to the carbon with one hydrogen atom first. Would that be wrong ?
so it does not matter which double bonded carbon atom is positive ?Oh I see. Well I'm not sure but I think order of bonding (which carbon bromine bonds to first) should not matter.
If it does then someone else should correct me
The carbon that is lacking a bond is positively charged.so it does not matter which double bonded carbon atom is positive ?
It can never be 6, because if you divide 6 Carbons into two molecules, each molecule will have 3 Carbons. You can't make any non-cyclic isomer out of propane. So 6 is not an option.View attachment 59772
I understand that A and C are not correct but I am confused between B and C.......... When it comes to cyclic isomers, won't propene and butene both have them?
Can anyone help me out?
Thnx
I thought only the CH3 which is near to OH was the only chiral center, because it was the only one which was sp3 hybridizied and had four different groups attached but how is the answer D?? View attachment 59774
Can you please explain why? Shouldn't the chiral centers have four different substituent groups attached?View attachment 59775
I think these all are the chiral centers for this molecule.
View attachment 59773
So I can understand that carvone is a ketone and 2-4 DNPH is a test for carbonyl group, but how will I know that what amount of molecules react with 2,4 DNPH??
Ohhhhh RIGHT!It can never be 6, because if you divide 6 Carbons into two molecules, each molecule will have 3 Carbons. You can't make any non-cyclic isomer out of propane. So 6 is not an option.
thanks! I get thatView attachment 59776
After the reaction with Concentrated, Hot, KMnO4 you get a molecule as shown above.
There're 4 carbonyl groups. 1 molecule of 2,4 DNPH reacts with 1 carbonyl. As there're are 4 carbonyl groups, so you'll need 4 molecules of 2,4 DNPH.
2,4 DNPH reacts with a carbonyl group like this:
View attachment 59777
wait, can you tell me which reaction was that when ketone reacted with potassium manganate solution?View attachment 59776
After the reaction with Concentrated, Hot, KMnO4 you get a molecule as shown above.
There're 4 carbonyl groups. 1 molecule of 2,4 DNPH reacts with 1 carbonyl. As there're are 4 carbonyl groups, so you'll need 4 molecules of 2,4 DNPH.
2,4 DNPH reacts with a carbonyl group like this:
View attachment 59777
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