Chemistry: Post your doubts here!

[Holmes]

PLZ explain!!

9701/13/M/J/12

 

[Holmes]

9701/13/M/J/12

 

[Holmes]

9701/13/M/J/12

 

[Holmes]

9701/12/M/J/12

 

[Holmes]

9701/12/M/J/12

 

[Holmes]

9701/13/O/N/13

 

[Holmes]

what does he want?

9701/13/O/N/13

 

[Holmes]

9701/11/M/J/14

 

[Holmes]

9701/11/M/J/14

 

[Holmes]

teach me this question thoroughly


9701/11/M/J/14

 

[Mstudent]

View attachment 62429
9701/11/M/J/13

Go to the data booklet, there you'll find 4. Standard Electrode potential ................................, there you'll find the equation for oxidation of Sn2+ to Sn4+ and reduction of KMNO4, just balance them so that the mole ratio of electrons is the same on both sides and then add the two equations, the electrons will cancel out to give you the equation, and then you know the rest!

 

[Mstudent]

teach me this question thoroughly

View attachment 62440
9701/11/M/J/14

what's the answer?

 

[darks]

Could you plz send it to me??? Your help will be greatly appreciated!

36. is A ONLY NaBr and NaI are oxidised when reacted with dil H2SO4, NaCL is too strong to be oxidised
37 is B I suppose? Find 'n' from PV=NRT to find the gas with the least moles!

hope that helps

Thanks!

March 2017 P1 for you all

 

[Holmes]

9701/11/O/N/13

 

[Holmes]

what's the answer?

C

 

[darks]

teach me this question thoroughly

View attachment 62440
9701/11/M/J/14

N-N bond breaks as it is very weak (energy 160 Kj/mol). NF2 is the single product. Statement 1 is incorrect. Statement 2 is correct as 160 is the energy of the bond that breaks. Molecules non linear as a lone pair present on N of NF2

 

[darks]

View attachment 62435
9701/12/M/J/12

Solve for each equation.
I will only show for D, which is the right answer.
Initial moles of P = 2 mol
mol at equilibrium of R = x
so for equation D,
mol at equilibrium of P = 2 - x
mol at equilibrium of Q = x/2
Sum of all mol at equilibrium expressions
x+(2-x)+(x/2)
Simplifies to [2+(x/2)] which should be the total moles according to the question.

 

[Holmes]

Go to the data booklet, there you'll find 4. Standard Electrode potential ................................, there you'll find the equation for oxidation of Sn2+ to Sn4+ and reduction of KMNO4, just balance them so that the mole ratio of electrons is the same on both sides and then add the two equations, the electrons will cancel out to give you the equation, and then you know the rest!

Appreciations and a thunderous Applause for you.
Thank you teacher.

 

[Mstudent]

Thanks!

March 2017 P1 for you all

Thanks bro!

 

[Mstudent]

Appreciations and a thunderous Applause for you.
Thank you teacher.

Yo are very welcome, anytime