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Chemistry: Post your doubts here!

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teach me this question thoroughly

View attachment 62440
9701/11/M/J/14
N-N bond breaks as it is very weak (energy 160 Kj/mol). NF2 is the single product. Statement 1 is incorrect. Statement 2 is correct as 160 is the energy of the bond that breaks. Molecules non linear as a lone pair present on N of NF2
 
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Solve for each equation.
I will only show for D, which is the right answer.
Initial moles of P = 2 mol
mol at equilibrium of R = x
so for equation D,
mol at equilibrium of P = 2 - x
mol at equilibrium of Q = x/2
Sum of all mol at equilibrium expressions
x+(2-x)+(x/2)
Simplifies to [2+(x/2)] which should be the total moles according to the question.
 
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Go to the data booklet, there you'll find 4. Standard Electrode potential ................................, there you'll find the equation for oxidation of Sn2+ to Sn4+ and reduction of KMNO4, just balance them so that the mole ratio of electrons is the same on both sides and then add the two equations, the electrons will cancel out to give you the equation, and then you know the rest!

Appreciations and a thunderous Applause for you.
Thank you teacher. ;)
 
Messages
438
Reaction score
3,645
Points
253
N-N bond breaks as it is very weak (energy 160 Kj/mol). NF2 is the single product. Statement 1 is incorrect. Statement 2 is correct as 160 is the energy of the bond that breaks. Molecules non linear as a lone pair present on N of NF2

Thanks bro
 
Messages
438
Reaction score
3,645
Points
253
Solve for each equation.
I will only show for D, which is the right answer.
Initial moles of P = 2 mol
mol at equilibrium of R = x
so for equation D,
mol at equilibrium of P = 2 - x
mol at equilibrium of Q = x/2
Sum of all mol at equilibrium expressions
x+(2-x)+(x/2)
Simplifies to [2+(x/2)] which should be the total moles according to the question.
can you plz be more clear
 
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Holmes
For papers from 2013 and 2012, I have created some videos to explain the MCQs. You can search through the playlists

 
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603
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Points
153
A.
Why is 3 correct?

Increasing the pressure also increases the concentration of the gaseous reactants, therefore the rate of backward is also expected to increase.

However, the equilibrium will still shift to the right as the increase in the rate of the forward reaction is more than the increase in the rate of backward reaction.
 
Messages
603
Reaction score
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Points
153
I can't see the right side of the question, should I assume that the charge is -3?

Sodium metal will react with carboxyl groups COOH and hydroxyl OH groups to form COO- and O-. So if we have a total of 3 such groups, it will form a -3 charge

Sodium hydroxide will react with COOH and not OH
 
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can you plz be more clear
A- Inital: 2 : 0 : 0
Final : 2-x: 2x : x
Total moles: 2-2+2x+x = 3x so A is incorrect.

B-
Initial: 2 : 0 : 0
Final: 2-2x : 2x : x
Total moles: 2-2x+2x+x = 2+x so B is incorrect

C-
Initial: 2 : 0 : 0
Final 2-2x:x:x
Total = 2-2x+x+x = 2 incorrect

D-
Initial: 2 : 0 : 0
Final: 2-x : x/2 : x [x = 2R]
Total moles = 2-x+x/2+x =2+x/2 mols!
 
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M2017 p12 Q 22 anyone? http://papers.gceguide.com/A Levels/Chemistry (9701)/9701_m17_qp_12.pdf
Ans A can anyone explain why isnt it the other options??
Q26 Why isnt it A? doesnt Kmno4 oxidise secondary alcohol to ketone??

Q27 ??????????
Q 28 29
Metanoia
Holmes
Mstudent
HELP!!
Q22) C-Br bond longest and weakest (Br atomic radius largest) so C-Br bond will be the first to undergo homolytic fission.

Q26) You said it yourself, "ketone"... The product shown in A is not ketone, but an aldehyde. Ketone would be CH3COCH3.
 
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Q22) C-Br bond longest and weakest (Br atomic radius largest) so C-Br bond will be the first to undergo homolytic fission.

Q26) You said it yourself, "ketone"... The product shown in A is not ketone, but an aldehyde. Ketone would be CH3COCH3.

THANKYOUU n SRRY ABOUT Q 26 THIS IS WHEN I SOLVE A Q.P AT 3:00 AM.
CAN U PLZZ EXplain Q27??
if u hv time 19 n 10 too?
 
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