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Chemistry and Physics AS paper 12 MCQS
well for q29 since power is same so 12^2/Rx=6^2/Ry 12^2/6^2=Rx/Ry 4=Rx/Ry for Q17 well put in formula mgh 80*10*(2.5*6)(as there are 6 stairs) u get 12000 D is correct -
Chemistry and Physics AS paper 12 MCQS
;) no problem For Q1 Sn1 is two step reaction sn2 is one step reaction even in 3rd option u have cl attached to primary carbon so it is Sn2 reaction since option 2 is incorrect so we are left with 1 being correct intermediate means there is a two step reaction for Q2 well for option b u do know... -
Chemistry and Physics AS paper 12 MCQS
for Q3 to form ion2+ u need energy that is the sum of first and second ionisation when u refer to databooklet u will realize aluminium needs 1820+577=2397 and cobalt also needs 757+1640=2397 see energies are same for Q9 i will solve it i am tired at the moment -
Chemistry and Physics AS paper 12 MCQS
:) for question at lower temperature maxima shifts to left and at a greater value of Y (Y axis) only A is correct if u consider this i believe 27 is not a valid question hydrogen rich carbon in double bond will become more hydrogen rich here . it should be homolytic and 1:3 as 2-chloropropane... -
Chemistry and Physics AS paper 12 MCQS
perfect thanks for asking May God Shower his blessing upon u -
Chemistry and Physics AS paper 12 MCQS
for last question look the easiest method here is to visualize see (u are a charge) if u have only one route then the resistors are in series and if u go two or more routes then it is parallel. three 10 ohm resistors in series so add them this makes 1 30 ohm resistor which is parallel to 10 ohm... -
Chemistry and Physics AS paper 12 MCQS
for Q14 for the moment of forces, you'll have to consider the perpendicular distance form the point of application of force and the axis. in your case, 10N and 5N act counter-clockwise and the 15N acts clockwise. consider clockwise direction to be positive and then find the moments of forces... -
Chemistry and Physics AS paper 12 MCQS
yea sure buddy there u go well i had a appointment for a dentist so couldnt solve the remaining question sorry for making u wait for question 38 after beta decay element's proton increases by one here it becomes 4 mass number remains unchanged mass number 8 proton number 4 number of neutrons... -
Chemistry and Physics AS paper 12 MCQS
for Q27 the charge does move in direction of force applied by the charge as the centre of the circle the force applied is toward that charge inwards since the charge does not move in direction of force applied so that is zero. for Q29 electron will always move in direction parallel to the... -
Chemistry and Physics AS paper 12 MCQS
for Q9 let X2=A Y2=B X2y=C C^2/(A^2)*B=2 C^2=2*(A^2)*B SQUARE ROOT BOTH SIDES WE GET C=(2^0.5)*A*(B^0.5) anything raised to 0.5 means it is square rooted ok now for equation 2 we have A*(B^0.5)/C PUT IN VALUE OF C WE GET A*(B^0.5)/(2^0.5)*A*(B^0.5) thus we get... -
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Chemistry and Physics AS paper 12 MCQS
in HIO I has oxidation number of +1 in HIO3 I has oxidation number of +5 in I2 I has oxidation number of 0. look the oxidation number of element in L.H.S=R.H.S so multiply HIO by 5 to get +5 oxidation number thus balancing oxidation number in LHS and RHS. as there are 5 iodine ions in left so... -
Chemistry and Physics AS paper 12 MCQS
well PV=nRT we know number of moles wont change before and after the gases are mixed. T is also constant R is always constant so P1V1 for helium P2V2 for Neon P3V3 for mixed gases. P1V1+P2V2=P3V3 (5*12)+(6*10)=P3*15 solving this we get P3 as 8 -
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P1 MCQ's preparation thread for chemistry ONLY!!!!
for Q9 for solids there is no Kc or Kp so it wont be considered. initially there were 1 mole of Ag ion there were 0.44 moles of Ag ion left in equilibrium so 0.56 moles of Ag ion reacted to for 0.56 of Fe3+ we had initial 1 mole of Fe2+ as 1 mole of FeSO4 is available so we will have 0.44 moles... -
P1 MCQ's preparation thread for chemistry ONLY!!!!
mind if i help u here for Q4 nitrogen will have a lone pair as it should complete its octet right. we consider double bond and single bond to have same effect on the bond angle . we treat that(double bond) as one ok so here are 3 three pairs right 3 means trigonal planor .. because of lone... -
AS Physics Practical - Paper 34
thats great u were wise enough to realise -
AS Physics Practical - Paper 34
hahaha u people ratafied the guess ended up messing up every single thing -
AS Physics Practical - Paper 34
you could have been write has the examiner asked to add weight on the plunger and then measure the rate of flow but this was not the case... i thought it was written in english to remove the plunger maybe they didnt know what plunger is no problem