-
We need your support!
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
Search results
-
-
Chemistry: Post your doubts here!
i) mass of kerosene used = 8195 x 10.8 = 88506 kg = 88.506 tonnes ii) Form the equation for complete combustion of kerosene C14H30 + 21.5O2 --> 14CO2 + 15H2O Hint: to save time, a balanced equation is not required, as it can be observed that 1 mole of C14H30 produces 14 moles of CO2 Moles of... -
Chemistry: Post your doubts here!
A <--> B One way to think of it is that at higher temperatures, A and B both experience an increase in energies. So a larger portion of A is able to overcome the activation energy of the forward reaction to form B. At the same time, a larger portion of B is able to overcome the activation... -
Chemistry: Post your doubts here!
This is an instance where there could be confusion between the limited "school definition" and the wider scientific definition. H-bond donor : H attached to N, O, F H-bond acceptor: highly electronegative atom with partial negative charge N, O, F In this case, we do have H-bonding. H-bond... -
Chemistry: Post your doubts here!
Nicely done diagrams and explanation. :) I'll just like to add on that the 2nd product of the 3 compound would eventually be oxidized to HOOCCOOH and then to CO2. -
YouTube Videos on Past Year Chemistry MCQs
Based on my interactions with students in the academic forums, I have compiled a set of 20 calculation questions (some sample shown below) from past year papers that they often require help with. It is not surprising to find similar questions being repeated throughout the years, as such... -
Chemistry: Post your doubts here!
http://www.chemguide.co.uk/organicprops/carbonyls/addelim.html -
Chemistry: Post your doubts here!
Theoretically, one way would be to hydrolyze them with NaOH to form primary secondary and tertiary alcohols and then attempt to oxidize them with KMno4 1) tertiary would not be oxidized (no decolorization of KMnO4) 2) Primary would be oxidized to acid, secondary would be oxidized to ketone... -
Chemistry: Post your doubts here!
Based on 1st equation, 1 mole of NaN3 produces 1 mole of Na and 1.5 moles of N2. Based on the 2nd equation, the 1 mole of Na produced in the 1st reaction will then produce another 0.1 mol of N2. -
Chemistry: Post your doubts here!
You can check the half equations provided in the data booklet. -
Chemistry: Post your doubts here!
Should be B. The chiral carbon is the rightmost carbon on that molecule. And when viewed individually, none of the C=C carbons are holding two identical groups. ( although this seems to be more correctly known as E/Z isomers rather than cis trans) -
Chemistry: Post your doubts here!
http://onlineexamhelp.com/past-papers/cambridge-international-a-as-level/9701-chemistry-a-as-level-year-wise -
Chemistry: Post your doubts here!
The cold dilute KMnO4 adds 2 OH across the C=C bonds, the original OH on the bottom not oxidised to a ketone as it is not heated. So there will be 3 OH in the product. The hot KMnO4 cleaves the C=C bonds, you have only the bottom and 3rd from bottom rings with 6 carbons. -
Chemistry: Post your doubts here!
You need to subtract 1 isomer in this question as its a symmetrical molecule. The cis-trans and trans- cis are identical. -
YouTube Videos on Past Year Chemistry MCQs
I have uploaded solutions for 2014 papers These files will be charged at a nominal fee. I hope it would be useful to those who are interested. An image is attached to give you an idea of the layout of the contents. -
Solutions for 2014 MCQ for purchase at a nominal fee...
Solutions for 2014 MCQ for purchase at a nominal fee. http://metatutor.weebly.com/purchase-solutions-to-a-levels-mcqs-chemistry-9701.html- Metanoia
- Profile post
-
Chemistry: Post your doubts here!
I have uploaded solutions for 2014 papers http://metatutor.weebly.com/purchase-solutions-to-a-levels-mcqs-chemistry-9701.html These files will be charged at a nominal fee. I hope it would be useful to those who are interested. An image is attached to give you an idea of the layout of the contents. -
My webcam is currently faulty and so instead of recording videos, I am typing the solutions out...
My webcam is currently faulty and so instead of recording videos, I am typing the solutions out. In order to pay for the website,I might offer the sell the PDF files for downloading. The files will be ready in by the middle of this week for those who are interested.- Metanoia
- Profile post comment
-
Chemistry: Post your doubts here!
In this case, we divide equally because the question gives us the information that "a single product was obtained after oxidizing." We don't assume that we divide equally for all other questions unless the clues tells us so. As for your example of 5 carbons, there is no way to obtain a single...