• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Search results

  1. Metanoia

    Chemistry: Post your doubts here!

    Exactly. So we get ethanol and ethanoic acid. And the ethanol later gets oxidized to ethanoic acid. Giving us a single product in the end.
  2. Metanoia

    Chemistry: Post your doubts here!

    If we write it as NaCl + H2O --> NaOH + HCl The forward reaction really really really small compared to the backward reaction. The equilibrium lies very much to the left. Does the forward reaction happen? Not to any extent to make it significant.
  3. Metanoia

    Chemistry: Post your doubts here!

    one more could be if u place the CO group on second carbon atom rather than 3rd My concern is that these are actually "isomers of pentanone", not "isomers of penton-3-one". There is only one structure that penton-3-one, CH3CH2COCH2CH3. So the question wording is a bit strange.
  4. Metanoia

    Chemistry: Post your doubts here!

    You realized that you have actually formed an acid also? HCl. The reverse reaction is actually what would happen if there is NaOH and HCl. Its the neutralization reaction between HCl and NaOH.
  5. Metanoia

    Chemistry: Post your doubts here!

    Nope. NaCl is a neutral solution, But to explore your thoughts of it forming an alkaline solution, could you try to write an equation to that?
  6. Metanoia

    Chemistry: Post your doubts here!

    This sounds a bit strange, penton-3-one has only one structure.
  7. Metanoia

    Chemistry: Post your doubts here!

    I would really advised against checking the sum of moles of reactants vs products. Use the Initial/Change/Equilibrium table, that works for all cases.
  8. Metanoia

    Chemistry: Post your doubts here!

    Sodium chloride solution is neutral. The other 3 chlorides are acidic.
  9. Metanoia

    Chemistry: Post your doubts here!

    If we use the equilibrium table, it doesn't matter if the moles are different on both sides. We just adjust the values in the table accordingly. I'll create a imaginary reaction just for example, keeping the % as 33.3% .
  10. Metanoia

    Chemistry: Post your doubts here!

    That is the ester right? Then the question states that Q is hydrolyzed with sulfuric acid C4H8O2 --> acid + alcohol Then the mixture was oxidized to obtained a single product, R, in other words, the alcohol in the above reaction is oxidized to become the same compound as the acid. It simply...
  11. Metanoia

    Chemistry: Post your doubts here!

    Did you find out what is the formula of Q?
  12. Metanoia

    Chemistry: Post your doubts here!

    Yes. 2-chloropropanoic acid is stronger, this is due to the proximity of the electron withdrawing Cl to the COOH group. You can explain it either in terms of the weakened O-H bond before losing the proton or the stability of the anion after losing the proton. weakened O-H bond The O-H bond is...
  13. Metanoia

    Chemistry: Post your doubts here!

  14. Metanoia

    Chemistry: Post your doubts here!

    Do be very careful of the assumption that the total moles would remain constant, conceptually, it is wrong. It works in this unique question as the sum of the stoichiometric coefficients are the same on both sides. Using an example, hydrogen reacts with oxygen to form water 2H2 + O2 --> 2H2O...
  15. Metanoia

    Biology; Chemistry; Physics: Post your doubts here!

    MCQ Solutions to Chemistry 5070 for sale at http://metatutor.weebly.com/purchase-solutions-to-o-levels-mcqs-chemistry-5070.html. A sample is attached.
  16. Metanoia

    MCQ Solutions to Chemistry 5070 for sale (2007-2013)

    MCQ Solutions to Chemistry 5070 for sale at http://metatutor.weebly.com/purchase-solutions-to-o-levels-mcqs-chemistry-5070.html. A sample is attached.
  17. Metanoia

    Chemistry: Post your doubts here!

    Perhaps you should try to draw all the bonds out, especially on the CHO to convince yourself its an aldehyde functional group.
  18. Metanoia

    Chemistry: Post your doubts here!

    I think you meant 5 outer electrons, and it donates 1 each to the sulfur on both sides. Leaving 3 left. :)
  19. Metanoia

    Chemistry: Post your doubts here!

  20. Metanoia

    Chemistry: Post your doubts here!

Top