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  1. whitecorp

    Mathematics: Post your doubts here!

    The 2 comes from the 2sin^2 x part , and the 3 at the back gives you a total of 2+3=5.
  2. whitecorp

    Mathematics: Post your doubts here!

    5sin^x +3 cos ^x = 2 sin^2 x + ( 3sin^x +3 cos ^x) = 2sin^2 x + 3 Clearly, the maximum value of sin^2 x is 1 when x=pi/2, so the overall maximum value is simply 2+3 =5. (shown) Hope this helps. Peace.
  3. whitecorp

    Maths, Addmaths and Statistics: Post your doubts here!

    I have worked it out for you in full: Hope this helps. Peace.
  4. whitecorp

    Mathematics: Post your doubts here!

    It should be x^2 +bx+c, not ax^2+bx+c. The question only cited two sets of coordinates, which mean you can only have two unknowns, not three. Hope this helps. Peace.
  5. whitecorp

    Mathematics: Post your doubts here!

    Substitute in the two set of coordinates: 0=(-3)^2 - 3b+c ======> c=3b-9-------(1) -16= (-1)^2 -b + c ======> c =b-17 ---------(2) Equating (1) and (2) gives 3b-9 = b-17 or b=-4, c= -21 Therefore, the equation of the required parabola is y=x^2 -4x -21 . (shown) Hope this helps. Peace.
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