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Mathematics: Post your doubts here!
Here you go, the full solutions. Hope it helps. Peace. -
Mathematics: Post your doubts here!
Here you go, the full solutions. Hope it helps. Peace. -
Mathematics: Post your doubts here!
No problem, am glad it helped. Peace. -
Mathematics: Post your doubts here!
No problem, we all make mistakes at times. Peace. -
Mathematics: Post your doubts here!
You probably got zero because you took the y-coordinate of the first point and subtracted it from the x-coordinate of the second point. For two points (x1, y1) and (x2, y2), the gradient is simply given by m = (y1 - y2)/ (x1 -x2) [ or (y2 - y1)/ (x2 -x1) ] Hope this helps. -
Mathematics: Post your doubts here!
(iii) Notice that f(x) lies between 4-3=1 and 4+3=7 inclusive. Solving for f(x)=k can be interpreted as drawing a horizontal like y=k and finding the number of intersections with the y=f(x) curve. Hence, if no solutions arise, there are no intersections, ie k>7 or k<1. (iv) A function has... -
Mathematics: Post your doubts here!
Recognize in (ii) that acceleration is no longer a constant( ie not equals to g) and is now a function of time, hence the equations of motions no longer apply; you have to discover the expression for its velocity through one round of integration, and its displacement through a second round of... -
Mathematics: Post your doubts here!
If a circle of radius r is centered at (a,b), then its cartesian equation is given by (x-a)^2+ (y-b)^2 =r^2 . In your question, a=2 while b=0. Hope this helps. Peace. -
Mathematics: Post your doubts here!
The equation of this particular circle is simply (x-2)^2 + y^2 =r^2, where r denotes the radius of the circle. Substitute one set of coordinates into the above equation to compute the value of r, and subsequently substitute the remaining two sets of coordinates to verify they satisfy the circle... -
Mathematics: Post your doubts here!
I guess you are not using a graphic calculator then? If that is the case I am afraid you might have to consider other solving methods such as linear interpolation, newton raphson etc. Or you could try approximating e^(-x^4) as a Maclaurin's Series (perhaps up to and including the term in... -
Mathematics: Post your doubts here!
Try squaring both sides and shift all terms to one side of the inequality before trying to work things out. Hope this might help a little. Peace. -
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Mathematics: Post your doubts here!
Here you go, the full solutions: Hope this helps. Peace. -
Mathematics: Post your doubts here!
It would be much better if you can provide an attachment of the actual question. Peace. -
Mathematics: Post your doubts here!
The attachment you provided is the pure math portion, not mechanics. Please do check again. Peace. -
Mathematics: Post your doubts here!
Here are the solutions: Hope it helps. Peace. -
Mathematics: Post your doubts here!
Recognize that one pair of parallel sides lie along y=2x-4 and y=2x-13 (they have the same gradient value of 2), while the other pair lie along x+y=5 and x+y =-4 (they have the same gradient value of -1) . Graph out these 4 lines and convince yourself the above fact is correct. Next, based... -
Mathematics: Post your doubts here!
You would have to differentiate both sides wrt x, ie dy/dx = 4x + (-4x^3)* (e^-x^4) and set dy/dx=0. To obtain the roots of this equation, you will have to use your graphic calculator. Subsequently, you can either use the second order derivative or the sign test method to ascertain the nature... -
Full Version of A Level Mathematics Quick Tips Part 1 (android apps) now available
Thats interesting, thanks for sharing. I learnt a new thing today. Peace. -
Mathematics: Post your doubts here!
Let's just look at the left shaded area of the normal distribution curve which I previously have drawn. We assume the dotted line has a value of -a. Then we seek to find a through the following: P(Z<-a) = 0.1 =====> -a= invNorm (0.1) = -1.282 . If we examine the problem carefully, we realize...
