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Mathematics: Post your doubts here!
Sorry my bad, actually the answer scheme is correct. A continues to move upwards even as B remain on the floor. Since the string has slackened, tension in string now =0 N and the velocity of A decreases from 1.6 m/s to 0m/s under the influence of gravity. Let additional distance moved by A=s2... -
Mathematics: Post your doubts here!
For (i) I obtained an acceleration value of 4 m/s^2. (ii) Maximum height reached by A =distance B falls through before reaching the ground Let this be s. Then using v^2 =u^2 + 2as, substituting in the values, we have 1.6^2 = 0^2 +2 (4)(s) =====> s= 0.32 m (shown) (iii) Using s=ut +... -
Mathematics: Post your doubts here!
Oh no, I can't, my math is awful, terrible. Peace. -
Mathematics: Post your doubts here!
Appreciate the gesture, peace. -
Mathematics: Post your doubts here!
Consider the substitution y= 3^x. Hope this helps. Peace. -
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Mathematics: Post your doubts here!
Your identity is incorrect, the RHS should be 8 (cosx)^4 -3. I have provided the solution for this: For (ii), what equation exactly are you referring to? Note that (i) is an identity, there is nothing to solve for. Peace. -
Mathematics: Post your doubts here!
Did you mean to say one fourth? -
Mathematics: Post your doubts here!
There is symmetry involved here-the path of the ball on the way upwards, and that of the ball on the way downwards. Let initial velocity of the ball be u, then time taken to travel upwards =3/2 =1.5s When it attains its maximum height before falling downwards, velocity =0 Hence, 0= u +... -
Mathematics: Post your doubts here!
You may wish to refer to this which I previously solved for someone else: Solutions for Q9(ii) Hope it helps. Peace. -
Mathematics: Post your doubts here!
There you go, the full solutions. Hope it helps. Peace. -
Mathematics: Post your doubts here!
You will have to be more specific when articulating your needs (eg what topics you are currently studying, what exactly confuses you etc) so others can assist you efficiently. Good luck, stay optimistic. Peace. -
Mathematics: Post your doubts here!
Draw a right angled triangle, and label the opposite and adjacent sides as k and 1 respectively, such that the ratio of tan x is k/1=k The length of the hypotenus is then given by sqrt (k^2 +1) sin x is defined as opposite/hypotenus = k/ sqrt( k^2 +1) (shown) Hope this helps. Peace. -
Mathematics: Post your doubts here!
Absolutely correct. Peace. -
Mathematics: Post your doubts here!
Posting the question here would be nice. Peace. -
Mathematics: Post your doubts here!
Divide 2 pi sinx =pi -x by pi on both sides, we have 2 sinx = 1- x/pi = (-1/pi)*x +1 The line you have to sketch would be y=(-1/pi)*x +1 , where its gradient is simply -1/pi, and y-intercept value is 1. Hope this helps. Peace. -
Mathematics: Post your doubts here!
Replace y by 2x-x^2, do the necessary expansion and collect all relevant terms involving x^2. Hope this helps. Peace. -
Mathematics: Post your doubts here!
tan (pi -x) = -tanx =-k tan(pi/2 -x ) = cot x =1/tanx =1/k To find sinx, try drawing out a right angled triangle. Label the opposite side as k and the adjacent side as 1 such that tanx =k Then sin x =opposite side/ hypotenus side = k/ sqrt (k^2 +1) (shown) Hope this helps. Peace. -
Mathematics: Post your doubts here!
Reflect the original function in the line y=x, such that the domain of f^-1 (x) = range of f(x), and range of f^-1(x) =domain of f(x). Hope this helps. Peace. -
Mathematics: Post your doubts here!
Solutions for your vectors problem. Hope it helps. Peace.
