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  1. whitecorp

    Mathematics: Post your doubts here!

    Here are the workings for finding |z| when arg(z) is a maximum: Hope this helps. Peace.
  2. whitecorp

    Mathematics: Post your doubts here!

    In that case we shall consider two right-angled triangles to make the necessary calculations: Hope this helps. Peace. Edit: My bad, I read your question wrongly as asking to find arg(z) min. Will show you the workings for |z| when arg(z) is a maximum shortly.
  3. whitecorp

    Mathematics: Post your doubts here!

    Cheer up, here are the workings: Hope it helps. Peace.
  4. whitecorp

    Mathematics: Post your doubts here!

    Here are the workings: Hope this helps. Peace.
  5. whitecorp

    Mathematics: Post your doubts here!

    For Q10, I will require the answers from (i) and (ii) (a). Here are the solutions for Q7 (complex numbers Argand Diagram): Hope this helps. Peace.
  6. whitecorp

    Mathematics: Post your doubts here!

    No problem, peace.
  7. whitecorp

    Mathematics: Post your doubts here!

    That is correct, I teach A level H2 maths. Have a good day too. Peace.
  8. whitecorp

    Mathematics: Post your doubts here!

    The full solutions for this vectors problem here: Hope it helps. Peace.
  9. whitecorp

    Mathematics: Post your doubts here!

    The full solutions for this problem: Hope it helps. Peace.
  10. whitecorp

    Mathematics: Post your doubts here!

    Composed the full solution for this problem before rushing off to teach for the day : Hope it helps. Peace.
  11. whitecorp

    Mathematics: Post your doubts here!

    The full solutions for you here: Hope this helps. Peace.
  12. whitecorp

    Mathematics: Post your doubts here!

    sinA =2sinB -------(1) cosA +2 cosB =2 =======> cosA =2(1-cosB) -----------(2) Squaring (1), we have sin^2 A = 4 sin^2 B ----------(3) Squaring (2), we have cos^2 A= 4(1-cosB)^2 ---------(4) (3)+(4): 1= 4 sin^2 B + 4 (1-cosB)^2 1= 4 sin^2 B + 4 - 8cos B +...
  13. whitecorp

    Mathematics: Post your doubts here!

    gradient function of curve is dy/dx = 2x Since this particular tangent is parallel to the line y=x, then it must have a gradient value of 1 (compare this with the structure y=mx+c) Hence,we have 2x= 1 =====> x=0.5 When x =0.5, y= 0.5^2 =0.25 Therefore, the equation of the required...
  14. whitecorp

    Mathematics: Post your doubts here!

    There you go, the full solutions: Hope this helps. Peace.
  15. whitecorp

    Mathematics: Post your doubts here!

    What exactly do you mean by passing between the points? Does the curve pass through those two given points? If it does, you may wish to check if you have provided the correct set of coordinates. It is obvious the graph is strictly increasing but yet your two points have the same x-values...
  16. whitecorp

    Mathematics: Post your doubts here!

    dy/dt = -6sin2t, dx/dt= -2sint dy/dx = dy/dt divided by dx/dt = -6sin2t/-2sint = 3sin2t /sin t =3 (2sint cost)/sin t = 6 cost Since 0<t<pi, -6 <6cost <6 (shown) Note that dy/dx denotes the gradient function of the curve at a generic point for a parameter value of t. Hope this helps. Peace.
  17. whitecorp

    Mathematics: Post your doubts here!

    No problem. Peace.
  18. whitecorp

    Mathematics: Post your doubts here!

    To transform the expression, at the same time maintain the mathematical integrity of things.
  19. whitecorp

    Mathematics: Post your doubts here!

    If you drew out the curve, you will notice that the x-intercepts are x=0 and x=8; since we are looking at volume of revolution about the x-axis, those x-intercept values would give you your lower/upper limits of integration respectively. Hope this helps. Peace.
  20. whitecorp

    Mathematics: Post your doubts here!

    Here you go, the workings: Hope this helps. Peace.
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