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  1. Jaf

    Chemistry P41 How was it?

    2.5 x 10^9 :p Uptil now I haven't seen a good reason why this shouldn't be the answer.
  2. Jaf

    Chemistry P41 How was it?

    You're missing the point, again. +0.3V is NOT a standard value you can use. It is the DIFFERENCE between two values. That's not the same thing. Since we had nothing to compare our potential with (as you say), we can't say if the difference is more or less than 0.3V. You're using the 0.3V value...
  3. Jaf

    IBA and AKU test on the same day :/

    AKU + IBA? Yeh kya combination hua? :p
  4. Jaf

    S1 statistics pole :D :D :D

    Ok not going to derail the thread so final post about this. *too *irritating *don't On the contrary, I honestly think you'd benefit more from doing that! :LOL: I know it's the internet convention and all, but this is an educational forum. Typos are okay, we all make them. But I don't see the...
  5. Jaf

    *tosses life jacket at you*

    *tosses life jacket at you*
  6. Jaf

    S1 statistics pole :D :D :D

    Guys... = Pole
  7. Jaf

    Chemistry P41 How was it?

    If that's what you read, then you completely missed the point that was being made. It doesn't say at all that if the electrode potential of cell is less than 0.3, the reaction wouldn't occur. It says if the DIFFERENCE of the E°cell between the reaction under standard conditions and the reaction...
  8. Jaf

    Chemistry P41 How was it?

    Wait, I'm a bit lost too. What non-standard conditions? :S I do remember the equation mentioning something but only very faintly.
  9. Jaf

    A LEVEL RESULT QUERY......

    ^Hmmm... this is new! Thank you for that!
  10. Jaf

    Chemistry P41 How was it?

    LOL no. They only asked for the 'k' value. No units. I still gave the units though.
  11. Jaf

    Chemistry P41 How was it?

    Well the method COULD be used for the first part since it was more or less a 'prove' question. We knew the order was 1. So no problem there. It's the second part I'm getting worked up over. Oh well...
  12. Jaf

    A LEVEL RESULT QUERY......

    If you did not appear for a paper you will be given a U (ungraded). I had to miss all of my papers in one session and I got a certificate that said U for all the subjects.
  13. Jaf

    Chemistry P41 How was it?

    About the rate of reaction question... I just didn't think half-life was the method to do it. (at our level, especially using only a graph; you would need differentiation if it were a second order reaction and since we didn't know, we shouldn't use half life) I drew a tangent for the first curve...
  14. Jaf

    Mathematics: Post your doubts here!

    I see. Thank you so much.
  15. Jaf

    Mathematics: Post your doubts here!

    Dude, just multiply your two answers from part i) to get one quadratic factor and find the other one by (Ax^2 + Bx + C) inspection. That is, the roots you get in i) are 1 - √2 i and 1 + √2 i. So the factors become (x-1+√2 i)(x-1-√2 i). You multiply the brackets and you'll see everything in...
  16. Jaf

    Mathematics: Post your doubts here!

    The issue I had with the answer to this is that instead of rounding off to 0.693 before substitution into the equation, I continue to use cuberoot of 1/3, and end up getting a different answer for the x coordinate (the difference is quite a bit actually). Confusing. :S
  17. Jaf

    Mathematics: Post your doubts here!

    Question 7 part ii) http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_33.pdf Please! The er says something about symmetry. Donno what!! Ashique bro? :love:
  18. Jaf

    Physics: Post your doubts here!

    http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_w05_qp_4.pdf Question 5)b)ii) If we increase the p.d., the velocity of the particle electron will decrease. By F=Bqv, the force acting on the particle should also decrease and hence the...
  19. Jaf

    Results

    Yeh ziada hogaya ab. :p
  20. Jaf

    Chemistry: Post your doubts here!

    Recall that conjugate acids have one extra proton compared to their conjugate bases. See which one of the two compounds have one extra proton attached to it (H+) = HPO^(2–) and H2PO4^(-) It's pretty obvious it's the latter: H2PO-. So this will act as you acid (or proton donor). The other one...
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