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  1. Mathemagical

    Chemistry: Post your doubts here!

    Treat the dipoles as vectors. The C-Cl bonds are in opposite directions, so they cancel out each other.
  2. Mathemagical

    Chemistry: Post your doubts here!

    The direction of the arrow points toward the compound, and as the term "formation" suggests, it is the correct direction and thus the sign is +.
  3. Mathemagical

    Chemistry: Post your doubts here!

    This is similar to the other question above. Increase in pressure will increase both forward and backward rates, but by different amounts. In this case, the forward will be speeded up more than the backward.
  4. Mathemagical

    Chemistry: Post your doubts here!

    2 moles of water are formed, and the arrow is pointed in the correct direction, so it is +2 multiplied by the enthalpy of formation of water.
  5. Mathemagical

    Chemistry: Post your doubts here!

    This is a trick many students fall for. Increasing the temperature increases both forward and backward rates, but due to the equilibrium position, it would increase the rate of the backward reaction by a relatively larger amount.
  6. Mathemagical

    Chemistry: Post your doubts here!

    The question states that vigorous effervescence occurred, so naturally I would opt for C, because Barium is the most reactive element amongst the other choices.
  7. Mathemagical

    Chemistry: Post your doubts here!

    For this, I suggest learning the ICE Tables Method. Here's the link for it: http://tinyurl.com/lv2hlh9
  8. Mathemagical

    Chemistry: Post your doubts here!

    You're asking the wrong questions here. For every change in temperature, pressure or some other condition you have to know that it may affect one or both of the equilibrium or rate. The answer is D because removing ammonia would not alter the rate, whereas increasing the temperature and pressure...
  9. Mathemagical

    Chemistry: Post your doubts here!

    A complete outer shell has 8 valence electrons, whereas Boron only has 6 in BF3.
  10. Mathemagical

    Chemistry: Post your doubts here!

    This is a useful diagram you can refer to.
  11. Mathemagical

    Chemistry: Post your doubts here!

    Aldehydes and ketones would not react with any of those.
  12. Mathemagical

    Chemistry: Post your doubts here!

    No, they do not react.
  13. Mathemagical

    Chemistry: Post your doubts here!

    NaOH is basic, so carboxylic acids would react with it. However, alcohols would not.
  14. Mathemagical

    Chemistry: Post your doubts here!

    Yes, the question is on balancing reactions. Option A is the only hydrocarbon that can balance the reaction.
  15. Mathemagical

    Chemistry: Post your doubts here!

    Both alcohols and carboxylic acids react with sodium metal. Follow these links for further information: Alcohols: http://tinyurl.com/bawcd94 Carboxylic acid: http://tinyurl.com/5r72ms However, only carboxylic acids react with sodium carbonate in a neutralisation reaction, not alcohols. The...
  16. Mathemagical

    Chemistry: Post your doubts here!

    Mass of ice = Volume*Density = 1.00*1 = 1g Number of moles = 1/18 From here on, apply the formula pV=nRT to calculate V.
  17. Mathemagical

    Chemistry: Post your doubts here!

    You see, hydrogen bonds are very much an intermolecular force as they are an intramolecular one. This is still a grey area, but for simplicity's sake we can ignore the possibility of it forming hydrogen bonds with water.
  18. Mathemagical

    Chemistry: Post your doubts here!

    Option 3 is wrong because it could either be an alcohol or a carboxylic acid. There is no observation which confirms either of these, so we cannot assume that it is an alcohol definitely.
  19. Mathemagical

    Chemistry: Post your doubts here!

    Option 2: Halogenoalkanes have less H atoms because they are replaced by halogens, so they form hydrogen bonds less readily. Option 3: Alkanes cannot undergo addition polymerisation. Therefore, they are both wrong.
  20. Mathemagical

    Chemistry: Post your doubts here!

    In NH4ClO4, the oxidation state of chlorine is +7, so it is reduced to -1 in AlCl3. N increases from -3 to 0. Remember that in the ammonium ion, NH4+, the oxidation state of N is -3 and that of H is +1.
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