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  1. Mathemagical

    Chemistry: Post your doubts here!

    Question 29: With the addition of cold dilute KMnO4, two alcohol groups will be added to the carbon-carbon double bond which will in turn form a single bond, hence creating 2 new chiral carbons. The addition of hot concentrated KMnO4 will oxidise the secondary alcohol group on the left to a...
  2. Mathemagical

    Chemistry: Post your doubts here!

    Question 22: After polymerising the alkenes they become saturated and so they will not undergo reactions such as hydration and oxidation. Therefore, the answer is C. Question 27: Options A and B are incorrect because they do not have CH2CO2CH3 parts in their compounds. Option D is also...
  3. Mathemagical

    Chemistry: Post your doubts here!

    This is a tricky one, but it can be done by elimination. B, C and D suggest that the compound may be MgCl2, PCl5 or NaCl. However, the reactions of the above with water are as such: MgCl2 + 6H2O --> 2Cl- + [Mg(H2O)6]2+ ; pH 6.7 PCl5 + 4H2o -->H3PO4 + 5HCl ; pH 2 NaCl + H2O --> Na+ + Cl- +H2O...
  4. Mathemagical

    Chemistry: Post your doubts here!

    Alcohols react with sodium metal to form a salt and hydrogen. For more information visit: http://tinyurl.com/bawcd94
  5. Mathemagical

    Chemistry: Post your doubts here!

    6NaOH + 3Cl2 --> 5NaCl + NaClO3+3H2O The mole ratio of Cl2:NaClO3 is 3:1, so 0.6/3=0.2 mol of NaClO3 will be formed. Mr of NaClO3 = 106.5 Mass = 0.2*106.5 = 21.3g Remember, NaClO is only formed with cold sodium hydroxide solution
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