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  1. The Sarcastic Retard

    tang maat kalo meko :P

    tang maat kalo meko :P
  2. The Sarcastic Retard

    How was papper 9701 / 12 chem MCQ ?

    I dont remember the option but I chose the one in which I got to know both are oxidized. :P
  3. The Sarcastic Retard

    How was papper 9701 / 12 chem MCQ ?

    39 wasn't D. :P It was B. :D
  4. The Sarcastic Retard

    How was papper 9701 / 12 chem MCQ ?

    It was Ionic.. :) It was asked in elements not between (y)
  5. The Sarcastic Retard

    How was papper 9701 / 12 chem MCQ ?

    Oh sorry, I worte B as well... :D
  6. The Sarcastic Retard

    *Inbox*

    *Inbox*
  7. The Sarcastic Retard

    How was papper 9701 / 12 chem MCQ ?

    Reactions at anode is always oxidation. I guess C was the answer.
  8. The Sarcastic Retard

    How was papper 9701 / 12 chem MCQ ?

    awesomaholic101 DarkEclipse
  9. The Sarcastic Retard

    How was papper 9701 / 12 chem MCQ ?

    It was easy (y) Ionic. (Same debate in our class too) :p 39 - A 40 -A (same debate.. :p) What was that answer?? :p GT - 30-32
  10. The Sarcastic Retard

    (Y)

    (Y)
  11. The Sarcastic Retard

    Chemistry: Post your doubts here!

    I solved this somewhere... I dont remember scroll pages back or type question paper in search and press cntrl F and type 34 and then 36. :)
  12. The Sarcastic Retard

    Chemistry: Post your doubts here!

    Can u ask him to elaborate ? :)
  13. The Sarcastic Retard

    Chemistry: Post your doubts here!

    29) A B C are correct, so D will be wrong.. (D just has one EZ cis trans in the middle) 27) Initiation step involves homolytic bond fission. So 1-chloropropane can take places of 6 hydrogen atom and 2-chloropropane can take only of 2. so ratio is 6 : 2 i.e 3 : 1
  14. The Sarcastic Retard

    Chemistry: Post your doubts here!

    dude u wrote 27 above and now u are asking 29. Which one do u want? :)
  15. The Sarcastic Retard

    Chemistry: Post your doubts here!

    Outta ma mind what is this?? xD
  16. The Sarcastic Retard

    Chemistry: Post your doubts here!

    http://www.compoundchem.com/wp-content/uploads/2014/11/VSEPR-Shapes-of-Molecules.pdf See 3rd last one.. Hope this helps. :)
  17. The Sarcastic Retard

    Chemistry: Post your doubts here!

    11 is theory part, refer to book. :) 21 : Its a major product so one Br will be attached to the carbon atom (of = bond) with less hydrogen attached to it. If I skiped any question do tell me. I was in hurry.
  18. The Sarcastic Retard

    Chemistry: Post your doubts here!

    I am not sure about 34 coz I made a guess.. :3 38. 1) It will form C4O2H8 so answer is C. ;)
  19. The Sarcastic Retard

    Chemistry: Post your doubts here!

    4Na + O2 ---> 2Na2O n of O2 = 0.0125mol (0.3/24) so n of Na = 4* n pf O2 so n of Na = 0.05mol Mass 0f Na = 1.15 Mr = 1.15/0.05 = 23. Thats correct.
  20. The Sarcastic Retard

    Chemistry: Post your doubts here!

    The remaining doubts re !! :P
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