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  1. The Sarcastic Retard

    Last minute preparation on MCQS 9701 and 9702. Discussion here.

    YOU MAKE YOUR OWN, without looking at anything.. :) The missout ones practice them by writing 5 times... :P You'll get it :D
  2. The Sarcastic Retard

    Chemistry: Post your doubts here!

    I will solve after sometime
  3. The Sarcastic Retard

    Last minute preparation on MCQS 9701 and 9702. Discussion here.

    Hehe... I made a chart by maself.. :P now I remember everything xD
  4. The Sarcastic Retard

    Its hard to get admission there. :) I will get in to it after Bsc. :) u are tryin? :P

    Its hard to get admission there. :) I will get in to it after Bsc. :) u are tryin? :P
  5. The Sarcastic Retard

    Last minute preparation on MCQS 9701 and 9702. Discussion here.

    Gokhapatiiiiiii!! :P Ratafication (y)
  6. The Sarcastic Retard

    Chemistry: Post your doubts here!

    I used trial and error. I tried option A, didnt satisfied the answer, but B did. Sth like this; Initial moles of 2P : 2 IM of 2Q and R : 0 Equilibrium moles of R : x EM of 2Q is x/2 (1:2 ratio) EM of 2P is 2 - x/2 (1:2 ratio and IM was 2 so we will subtrct x/2) So addition of EM = 2 - x/2 + x/2...
  7. The Sarcastic Retard

    Chemistry: Post your doubts here!

    It will replace H of OH only. (y) H2O ; D2O H2O ---> H+ + OH- D2O ---> D+ + DH-
  8. The Sarcastic Retard

    Chemistry: Post your doubts here!

    THere are two posiblities of forming alkenes in primary Halogenoalkane. There is only one posiblity of forming alkene in tertiary. Hence:
  9. The Sarcastic Retard

    Chemistry: Post your doubts here!

    CH3SH + 3O2 ----> CO2 + SO2 + 2H2O
  10. The Sarcastic Retard

    Chemistry: Post your doubts here!

    Hydrolysis in 2 and 3 1 cant be. :)
  11. The Sarcastic Retard

    Chemistry: Post your doubts here!

    Mr of ethanol = 46 Mr of ethanoicacid = 60 n of ethanol = 0.05mol 1 : 1 ratio mass of ethanoicacid = 0.05 * 60 * 70% = C
  12. The Sarcastic Retard

    Chemistry: Post your doubts here!

    https://www.xtremepapers.com/community/threads/last-minute-preparation-on-mcqs-9701-and-9702-discussion-here.42450/page-7#post-942645
  13. The Sarcastic Retard

    Last minute preparation on MCQS 9701 and 9702. Discussion here.

  14. The Sarcastic Retard

    Chemistry: Post your doubts here!

    Got it wait.. I will send pic. :)
  15. The Sarcastic Retard

    Chemistry: Post your doubts here!

    He is talking aabot starting and that would be same for rest. :)
  16. The Sarcastic Retard

    Last minute preparation on MCQS 9701 and 9702. Discussion here.

    Energy needed for all is same right? So that energy = -33.4KJ/mol Try for every option in which do we get less number of moles of CO2 For B : (33.4/890) = 0.03 For C : (33.4/715) = 0.05
  17. The Sarcastic Retard

    Chemistry: Post your doubts here!

    Ok So here, there will be same 2 cis trans isomer so answer is C.
  18. The Sarcastic Retard

    Last minute preparation on MCQS 9701 and 9702. Discussion here.

    moles of SO3 2- : moles of electrons : moles of metal 0.0025 : ? : 0. 005 1 :? : 2 1 : 2 : 2 2 mol of metal gained 2 mol of electrons 1 mol of metal gained 1 mol of electron (oxidation state will thus decrease by 1) Original oxidation state of metal = +3 Final oxidation state = +3 - 1 = +2...
  19. The Sarcastic Retard

    Chemistry: Post your doubts here!

    awesomaholic101 do u remember this explanation?? :p
  20. The Sarcastic Retard

    Yes.

    Yes.
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