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P1 MCQ's preparation thread for chemistry ONLY!!!!
23. The mole fraction of ethene is 1/2. If the products can be only methane, ethene and propene, there must be 2 ethene molecules, 1 methane molecule and 1 propene molecule, so that the mole fraction of ethene = 1/2. What you can do now is draw 2 ethene molecules, 1 methane molecule and 1... -
AS Physics P1 MCQs Preparation Thread.
10. The man's motion is similar to the motion of a ball thrown upwards, except that when you throw a ball upwards, there is no horizontal component for the velocity (the ball moves only up and down, not sideways). The man's motion is a parabolic trajectory (projectile motion); the horizontal... -
AS Physics P1 MCQs Preparation Thread.
9. The initial momentum = mv, so the final too must = mv. That rules out C & D. 15. GPE at the top = 2 x 3 x 9.81 = 58.86 J. WD against friction = 5 x 7 = 35 J. 58.86 - 35 = 23.86 J. 23.86 = 1/2 x 2 x v^2. Solve for v. 16. P =Fv = 80 x 9.81 x (50/100). 25. 31. Q=It. Q=10. Qn=10... -
AS Physics P1 MCQs Preparation Thread.
You right-click 'reply' then click 'open in a new tab' and under the box you'll see 'upload a file'. -
Chemistry and Physics AS paper 12 MCQS
15. The oxidation number of Ag in AgCl is 1+; in the [Ag(S2O3)]3- ion, it's 1+ too. Therefore B, C & D are ruled out. -
Chemistry: Post your doubts here!
8. You must draw a Hess cycle for this: 590 is the first ionisation energy, and 1150 is the second. 28. You first draw the structural formula of the monomer, then the skeletal: -
Chemistry: Post your doubts here!
Angles between 109 and 110 are for tetrahedral molecules with 4 bonds. SiO2 has a tetrahedral structure, that's known; so does propane. If you draw the structure of ethanoic acid, you'll see that one C is attached to 4 other groups, therefore the bond angle for it must be 109.5. That leaves... -
PAPER 1 MAY/JUNE 2013 PHYSICS DOUBTS HERE
Anybody doing the 2013 May/June Physics paper 1 can post their doubts here/discuss questions & answers here. -
AS Physics P1 MCQs Preparation Thread.
The gradient of a displacement-time graph is the speed/velocity. Acceleration is change in velocity. The question says that acceleration decreases; that means we can rule out B because it shows deceleration. Next the question says that the ball eventually reaches terminal velocity; that is, a... -
AS Physics P1 MCQs Preparation Thread.
7. Gravitational force is always down, so g must always be down since it's constant and it must always be negative since they say that upwards must be positive. 9. In parabolic motion, the horizontal component of the velocity stays constant, therefore the horizontal acceleration is always zero... -
AS Physics P1 MCQs Preparation Thread.
The principle of conservation of momentum says that the initial momentum must = the final momentum. The initial momentum = 2mu-mu=mu. Momentum in A, C and D = mu. Momentum in B = 0.33333. Therefore B is inconsistent with the principle of conservation of momentum. -
AS BIOLOGY P-33
The xylem is always to the inside. Check google images for drawings. -
AS BIOLOGY P-33
42 EPGU - 10 SMU 1 EPGU - x SMU 42x - 10 x - 10/42 = 0.238 SMU 1 SMU - 0.01 mm 0.238 SMU - x mm x - 0.01 x 0.238 = 0.00238 mm Therefore, step 1: 10 divided by 42 = 0.238 x 0.01 = 0.00238 mm. Step 2: 0.00238 multiplied by 1000 = 2.38 micrometres. -
AS BIOLOGY P-33
No problem. If you look at the picture again, there are 10 divisions between 2 and 3. That means between the 3 and 2, there's 10 units (because you have to count all the lines). -
AS BIOLOGY P-33
Because 20 is at 0 and 30 at 9. Therefore 30-20=10 corresponds to 9. And I myself don't understand the table in the mark scheme, heh. I only checked the final answer and it matched the one I got, so I guess the method I used is correct. -
AS BIOLOGY P-33
Number of eyepiece graticule units: 8.75-1.50=7.25 EPG units. (You have to measure the width of the lumen.) Now you can see on the second Fig. that 10 units of the stage micrometer are in line with 9 units on the EPG. You've got all the information you need, now all you need to do is cross... -
POLL: Chem paper 33 2013
Any Group 1 metal whose Ar is closest to the Ar you calculated. -
AS PHY PRACTICAL 33
You have to say that the values you used to calculate k were, for instance, 3 significant figures, so k too has to be 3. And if you use two values to calculate k, one 2 significant figures and the other 3 significant figures, then k can be either 2 or 3 significant figures. -
AS PHY PRACTICAL 33
Err, I'm afraid out teacher never told us anything like that. -
Chemistry paper 33 how was it?
Well, I performed the test for nitrite, the adding dilute acid to get a gas test, and I did get bubbles of gas for FA6, so probably it was nitrite. Unless the bubbles were something totally unrelated!