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  1. soumayya

    need help on CHEM mCqS

    The answer is B...replace 1 R group by H since an aldehyde contains an H atom bonded to the C of the -CO group...replace the -CN group by -CH2CO2CH3 in the second molecule since it behaves lyk -CN... hpe zat hlps...
  2. soumayya

    Hydrogen Bonding--chemistry

    hydrogen bonding is a form of permanent dipole-dipole force...that's wat i learnt..
  3. soumayya

    Hi everyone!

    u're welcme..
  4. soumayya

    suggestion

    what's zat...???
  5. soumayya

    Hey Errrbody :D

    welcome hre..
  6. soumayya

    P2 AND P3 DOUBT PLZZZZZ HELP SOLVING....

    constructing a geometrical progression.. 500 000, 550 000, .... a= 500 000, r = 1.1 ar^(n-1) > 4 000 000 500 000 * 1.1^(n-1) > 4 000 000 1.1^(n-1) > 8 taking log on both sides... (n-1) log 1.1 > log 8 n-1 > 21.82 we don't count the first term since it did not take 1 hr for the culture to...
  7. soumayya

    P2 AND P3 DOUBT PLZZZZZ HELP SOLVING....

    constructing a geometric progression...taking the first term to B 1... 1, 0.5, 0.25,... a= 1, r = 0.5 let ar^(n-1) = 0.05 0.5^(n-1)= 0.05 taking log on both sides... (n-1) log 0.5 = log 0.05 n-1= 4.322 we don't count the 1st term since it did not take 90 yrs to become 1...so we use the value...
  8. soumayya

    P2 AND P3 DOUBT PLZZZZZ HELP SOLVING....

    5) f(x) = ln (1+x) Let y = f(x) y = ln (1+x) e^y = 1+x x = e^y -1 f^(-1)= e^x - 1
  9. soumayya

    P2 AND P3 DOUBT PLZZZZZ HELP SOLVING....

    shouldn't it b ln instead of log..??
  10. soumayya

    P2 AND P3 DOUBT PLZZZZZ HELP SOLVING....

    4) 2 log 2x = 1+ log a log (2x)^2 = log 10 + log a log 4x^2 = log 10a 4x^2 = 10a x^2 = 5a/2 x = √5a/2
  11. soumayya

    Maths--functions..

    u're welcome..
  12. soumayya

    Maths--functions..

    When x=pi/2, f(x)= 2-0 = 2 2 is the greatest positive value we can get...
  13. soumayya

    Maths--functions..

    we don't learn how to sketch graph of cos^2 in A level..
  14. soumayya

    Paper 5 (Phy + Chem)

    here's the way my teacher taught me to answer the planning questions...it's better to answer pointwise, it,s clearer... hope that helps...
  15. soumayya

    A2 Chemistry P5

    u're welcome..
  16. soumayya

    Hi All

    welcome here...
  17. soumayya

    A2 Chemistry P5

    When ^Hsoln becomes more exothermic, this means that it becomes more negative...that is, it decrease..
  18. soumayya

    hellooooooo

    welcome to XPF...i fink there's a whole team hre to help u...u jst need 2 ask...
  19. soumayya

    Questions regarding Bonding.

    coordinate bonding is a special type of bonding in which one atom provides both shared electrons so as to attain a stable configuration...it's in A level...so no need to worry...
  20. soumayya

    A2 Chemistry P5

    As we move down Group I hydroxides, the bases become more soluble since the ^H soln becomes more exothermic...this is because of an increase in ionic radii of the cations from Li to Cs.... hope that helps...
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